如何更改Oracle服务器中表中xml字段的值

Question

我尝试在oracle服务器中名为HistEvents的表中将名为ANI_FATHER的字段的值从“DAD01”更改为“DAD01”。

字段ANI_FATHER位于表HistEvents中名为HEV_DETAILS的XML字段中，我不知道如何更改它的值。

<?xml version = '1.0' encoding = 'UTF-8'?><BIRTH Id="1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 
    <ANI_BIRTHDATE xsi:type="xsd:datetime">2015-12-31T00:00:00</ANI_BIRTHDATE> 
    <ANI_MOTHER>MOM01</ANI_MOTHER> 
    <ANI_FATHER>DAD01</ANI_FATHER> 
    <ANI_NUMGEN>F1</ANI_NUMGEN> 
    <ANI_NAIVE xsi:type="xsd:boolean">1</ANI_NAIVE> 
    <ANI_DATEIN xsi:type="xsd:datetime">2015-12-31T00:00:00</ANI_DATEIN> 
</BIRTH> 

Answer 1

create table test_xml(id number, xml_col xmltype); 

insert into test_xml values(1,xmltype(q'~<?xml version = '1.0' encoding = 'UTF-8'?><BIRTH Id="1" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 
    <ANI_BIRTHDATE xsi:type="xsd:datetime">2015-12-31T00:00:00</ANI_BIRTHDATE> 
    <ANI_MOTHER>MOM01</ANI_MOTHER> 
    <ANI_FATHER>DAD01</ANI_FATHER> 
    <ANI_NUMGEN>F1</ANI_NUMGEN> 
    <ANI_NAIVE xsi:type="xsd:boolean">1</ANI_NAIVE> 
    <ANI_DATEIN xsi:type="xsd:datetime">2015-12-31T00:00:00</ANI_DATEIN> 
</BIRTH>~')); 

1）第一方式。看起来更容易，但不推荐使用updateXml函数。

UPDATE test_xml SET xml_col = 
    updateXML(xml_col, 
      '/BIRTH/ANI_FATHER/text()', 
      'neW_VALUE') 
      WHERE ID =1 ; 

并检查结果

SELECT XMLSERIALIZE(DOCUMENT XML_COL) FROM TEST_XML WHERE ID= 1; 

1）推荐的方式。

UPDATE test_xml SET xml_col = 
    XMLQuery('copy $tmp := . modify 
      (for $i in $tmp/BIRTH/ANI_FATHER/text() 
      return replace value of node $i 
        with ''neW_VALUE2'') 
      return $tmp' 
      PASSING xml_col RETURNING CONTENT) 
    WHERE ID =1; 

XML Updating Queries to XQuery Update

Xpath tutorial