我有一个PHP脚本(粘贴在下面),它从URL列表中提取元数据,问题是可能需要一段时间才能加载,并且用户永远不知道它何时完成(除非他们留意他们的浏览器标签中的加载图标)在PHP脚本运行时添加加载图像
我一直在网上寻找很长一段时间,但找不到解决方案,我读过我可以使用Ajax,但我怎么能在这个脚本上使用它?
感谢您的帮助!
<script type="text/javascript">
function showContent(vThis)
{
// http://www.javascriptjunkie.com
// alert(vSibling.className + " " + vDef_Key);
vParent = vThis.parentNode;
vSibling = vParent.nextSibling;
while (vSibling.nodeType==3) { // Fix for Mozilla/FireFox Empty Space becomes a TextNode or Something
vSibling = vSibling.nextSibling;
};
if(vSibling.style.display == "none")
{
vThis.src="collapse.gif";
vThis.alt = "Hide Div";
vSibling.style.display = "block";
} else {
vSibling.style.display = "none";
vThis.src="expand.gif";
vThis.alt = "Show Div";
}
return;
}
</script>
<form method="POST" action=<?php echo "'".$_SERVER['PHP_SELF']."'";?> >
<textarea name="siteurl" rows="10" cols="50">
<?php //Check if the form has already been submitted and if this is the case, display the submitted content. If not, display 'http://'.
echo (isset($_POST['siteurl']))?htmlspecialchars($_POST['siteurl']):"http://";?>
</textarea><br>
<input type="submit" value="Submit">
</form>
</div>
<div id="nofloat"></div>
<div style="margin-top:5px;">
<h4><img src="expand.gif" alt="Show Div" border="0" style="margin-right:6px; margin- top:3px; margin-bottom:-3px; cursor:pointer;" onclick="showContent(this);" />Show me the script working!</h4>
<div style="margin-top:5px; display:none;">
<table class="metadata" id="metatable_1">
<?php
ini_set('display_errors', 0);
ini_set('default_charset', 'UTF-8');
error_reporting(E_ALL);
//ini_set("display_errors", 0);
function parseUrl($url){
//Trim whitespace of the url to ensure proper checking.
$url = trim($url);
//Check if a protocol is specified at the beginning of the url. If it's not, prepend 'http://'.
if (!preg_match("~^(?:f|ht)tps?://~i", $url)) {
$url = "http://" . $url;
}
//Check if '/' is present at the end of the url. If not, append '/'.
if (substr($url, -1)!=="/"){
$url .= "/";
}
//Return the processed url.
return $url;
}
//If the form was submitted
if(isset($_POST['siteurl'])){
//Put every new line as a new entry in the array
$urls = explode("\n",trim($_POST["siteurl"]));
//Iterate through urls
foreach ($urls as $url) {
//Parse the url to add 'http://' at the beginning or '/' at the end if not already there, to avoid errors with the get_meta_tags function
$url = parseUrl($url);
//Get the meta data for each url
$tags = get_meta_tags($url);
//Check to see if the description tag was present and adjust output accordingly
$tags = NULL;
$tags = get_meta_tags($url);
if($tags)
echo "<tr><td>$url</td><td>" .$tags['description']. "</td></tr>";
else
echo "<tr><td>$url</td><td>No Meta Description</td></tr>";
}
}
?>
</table>
</div>
<script type="text/javascript">
var exportTable1=new ExportHTMLTable('metatable_1');
</script>
<div>
<input type="button" onclick="exportTable1.exportToCSV()" value="Export to CSV"/>
<input type="button" onclick="exportTable1.exportToXML()" value="Export to XML"/>
</div>
</div>
你可以尝试修剪脚本到相关的位?阅读这些内容有点多。如果您不介意该网站只启用JavaScript,那么您可以使主页面显示一条加载消息,并踢出脚本,通过AJAX请求进行繁重的操作。如果你想要一个纯粹的PHP解决方案,那么可能会有大量的输出缓冲和冲洗 – GordonM 2012-04-25 09:11:46
当然!对于那个很抱歉! – RuFFCuT 2012-04-25 09:12:41