合并两个JSON对象为单个对象的Java

Question

我有一个像空两个JSON对象：

{"name":["Karbonn Smart A12 Star (Black & Silver)","Nokia 220 (Black)","Karbonn Smart A52 Plus (Black & Gold)","Karbonn Smart A12 Star (White & Gold)",.......]} 
{"price":["Rs. 3,699","Rs. 2,599","Rs. 2,499","Rs. 3,699",..........]} 

我想这两个对象组合就像下面我试图通过嵌套的每个循环它没有工作，我我不知道该程序来实现这一点：

{"mobile":[{"name":"Karbonn Smart A12 Star (Black & Silver)","price":"Rs. 2,499"}]...........} 

我的代码如下：

for(Element a:mobilename) 
    { 
    text= a.text(); 
    arr.add(text); 
    obj1.put("name", arr); 
    //a11.add(text); 

} 
    arr2.add(obj1); 

    for(Element b:price) 
    { 
    text1=b.text(); 
    arr1.add(text1); 

    obj.put("price", arr1); 




    } 
    arr2.add(obj1); 
    arr2.add(obj); 
    obj2.put("mobile", arr2); 

Answer 1

可以发现org.json这里JSON-java

import java.util.ArrayList; 
import java.util.List; 
import org.json.*; 

public class JsonTest 
{ 
    public String mergeJson(String name, String price) 
    { 
     JSONObject nameJ= new JSONObject(name); 
     JSONObject priceJ= new JSONObject(price); 
     JSONObject mobileJ = new JSONObject(); 

     JSONArray names = nameJ.getJSONArray("name"); 
     JSONArray prices = priceJ.getJSONArray("price"); 
     JSONArray mobiles = new JSONArray(); 

     if(names.length() == prices.length()) 
     { 
      for(int i=0;i<names.length();i++) 
      { 
       JSONObject mobile = new JSONObject(); 
       mobile.put("name", names.getString(i)); 
       mobile.put("price", prices.getString(i)); 
       mobiles.put(mobile); 
      } 
     } 

     mobileJ.put("mobile", mobiles); 

     return mobileJ.toString();   
    } 

    public static void main(String[] args) 
    { 
     String name = "{'name':['Karbonn Smart A12 Star (Black & Silver)','Nokia 220 (Black)','Karbonn Smart A52 Plus (Black & Gold)','Karbonn Smart A12 Star (White & Gold)','Karbonn Smart A50s (Black)','Karbonn Smart A52 Plus (White & Silver)','Karbonn Titanium S2 Plus (White)','Karbonn Smart A11 Star (Black)','Karbonn Smart A11 Star (White)']}"; 
     String price = "{'price':['Rs. 3,699','Rs. 2,599','Rs. 2,499','Rs. 3,699','Rs. 2,699','Rs. 2,499','Rs. 4,999','Rs. 4,399','Rs. 4,499']}"; 

     JsonTest test = new JsonTest(); 
     System.out.println(test.mergeJson(name,price)); 
    } 

} 

Answer 2

你可以通过for循环迭代，并在每次迭代创建新的JSONObject并把它添加到集合。最后将集合添加到mergedObject。例如。

import org.json.JSONArray; 
import org.json.JSONException; 
import org.json.JSONObject; 

import java.util.ArrayList; 
import java.util.Collection; 

public class Foo { 
    public static void main(String[] args) throws JSONException { 

     JSONObject object1 = new JSONObject("{\n" + 
       " \"name\": [\n" + 
       "  \"Karbonn Smart A12 Star (Black & Silver)\",\n" + 
       "  \"Nokia 220 (Black)\",\n" + 
       "  \"Karbonn Smart A52 Plus (Black & Gold)\",\n" + 
       "  \"Karbonn Smart A12 Star (White & Gold)\",\n" + 
       "  \"Karbonn Smart A50s (Black)\",\n" + 
       "  \"Karbonn Smart A52 Plus (White & Silver)\",\n" + 
       "  \"Karbonn Titanium S2 Plus (White)\",\n" + 
       "  \"Karbonn Smart A11 Star (Black)\",\n" + 
       "  \"Karbonn Smart A11 Star (White)\"\n" + 
       " ]\n" + 
       "}"); 

     JSONObject object2 = new JSONObject("{\n" + 
       " \"price\": [\n" + 
       "  \"Rs. 3,699\",\n" + 
       "  \"Rs. 2,599\",\n" + 
       "  \"Rs. 2,499\",\n" + 
       "  \"Rs. 3,699\",\n" + 
       "  \"Rs. 2,699\",\n" + 
       "  \"Rs. 2,499\",\n" + 
       "  \"Rs. 4,999\",\n" + 
       "  \"Rs. 4,399\",\n" + 
       "  \"Rs. 4,499\"\n" + 
       " ]\n" + 
       "}"); 


     JSONArray nameArray = object1.getJSONArray("name"); 
     JSONArray priceArray = object2.getJSONArray("price"); 

     JSONObject mergedObject = new JSONObject("{}"); 
     Collection<JSONObject> collection = new ArrayList<>(); 

     for (int i = 0; i < nameArray.length(); i++) { 
      JSONObject obj = new JSONObject(); 
      obj.put("name", nameArray.getString(i)); 
      obj.put("price", priceArray.getString(i)); 
      collection.add(obj); 
     } 

     mergedObject.put("mobile", collection); 
     System.out.println(mergedObject); 
    } 
} 

输出继电器：

{"mobile":[{"price":"Rs. 3,699","name":"Karbonn Smart A12 Star (Black & Silver)"},{"price":"Rs. 2,599","name":"Nokia 220 (Black)"},{"price":"Rs. 2,499","name":"Karbonn Smart A52 Plus (Black & Gold)"},{"price":"Rs. 3,699","name":"Karbonn Smart A12 Star (White & Gold)"},{"price":"Rs. 2,699","name":"Karbonn Smart A50s (Black)"},{"price":"Rs. 2,499","name":"Karbonn Smart A52 Plus (White & Silver)"},{"price":"Rs. 4,999","name":"Karbonn Titanium S2 Plus (White)"},{"price":"Rs. 4,399","name":"Karbonn Smart A11 Star (Black)"},{"price":"Rs. 4,499","name":"Karbonn Smart A11 Star (White)"}]}