圆括号内的Python间距

这里是我的打印功能

print("The text contains", totalChars, "alphabetic characters of which", numberOfe, "(", percent_with_e, "%)", "are 'e'.")

它打印出这样的

The text contains 5 alphabetic characters of which 5 (100.0 %) are 'e'.

但我需要它来打印这样

The text contains 5 alphabetic characters, of which 5 (100.0%) are 'e'.

唯一的区别似乎是间距围绕括号。我无法获得从一开始就被删除的空间。

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2016-11-15 ThunderBear

这听起来像你需要字符串格式。 –

您可以更好地控制参数间的间距（打印使用默认的空单）如果你使用str.format：

print("The text contains {} alphabetic characters\ 
     of which {} ({}%) are 'e'.".format(totalChars, numberOfe, percent_with_e))

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2016-11-15 14:19:12

如果你不能format这样做只是不提供它们作为不同的参数（使用默认sep的' '）。

也就是说，改造percent_with_e到str，并加入与+：

print("The text contains", totalChars, "alphabetic characters of which", numberOfe, "(" + str(percent_with_e) + "%)", "are 'e'.")

或者与format：

s = "The text contains {} alphabetic characters of which {} ({}) are 'e'".format(totalChars, numberOfe, percent_with_e) 

print(s) 
The text contains 5 alphabetic characters of which 5 (100.0) are 'e'

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2016-11-15 14:19:28

一个更简单的方法是将格式化为.format()方法的字符串：

print("The text contains {} alphabetic characters, of which {} ({}%) are 'e'".format(totalChars, numberOfe, percent_with_e))

如果您想继续使用逗号，你需要的sep关键字参数：

print("The text contains ", totalChars, " alphabetic characters of which ", numberOfe, " (", percent_with_e, "%) ", "are 'e'.", sep="")

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2016-11-15 14:19:40 zondo

这是与打印格式的问题。将多个参数传递给打印函数时，会自动插入空格。如果要格式化字符串，最好的方法是使用'％'运算符。

percent = "(%d%%)" % percent_with_e 
print("The text contains", totalChars, "alphabetic characters of which", numberOfe, percent, "are 'e'.")

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2016-11-15 14:21:38

圆括号内的Python间距

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