我试图读取图像文件,作为base64编码的字符串,并在连接使用HTTPS/SSL时输出数据字符串,否则将URL放在IMG src中属性如果它只在HTTP上。这是我目前的代码,但它不起作用。通过HTTPS服务图像的数据字符串,而在HTTP上的URL
<?php
function base64_encode_image($filename, $filetype) {
if (($_SERVER["HTTPS"] == "on") && $filename) {
$file = "/home/content/61/9295861/html/resource/image$filename";
$imgbinary = fread(fopen($file, "r"), filesize($file));
return "data:image/$filetype;base64," . base64_encode($imgbinary);
} else {
return $filename;
}
}
?>
<img src="<?php echo base64_encode_image('/resource/image/logo-96x72.png', 'png'); ?>" width="96" height="72" />
它输出:
<img src="<br />
<b>Warning</b>: fopen(/home/content/61/9295861/html/resource/image/resource/image/logo-96x72.png) [<a href='function.fopen'>function.fopen</a>]: failed to open stream: No such file or directory in <b>/home/content/61/9295861/html/theme/latest/index.php</b> on line <b>5</b><br />
<br />
<b>Warning</b>: filesize() [<a href='function.filesize'>function.filesize</a>]: stat failed for /home/content/61/9295861/html/resource/image/resource/image/logo-96x72.png in <b>/home/content/61/9295861/html/theme/latest/index.php</b> on line <b>5</b><br />
<br />
<b>Warning</b>: fread() expects parameter 1 to be resource, boolean given in <b>/home/content/61/9295861/html/theme/latest/index.php</b> on line <b>5</b><br />
data:image/png;base64," width="96" height="72" />
看到这个职位它可以帮助你。 http://stackoverflow.com/questions/3011222/dealing-with-http-content-in-https-pages – 2012-07-31 05:33:32
你这样做的任何理由?将图像嵌入base64完全消除了缓存图像的机会 - 您不会在带宽或ssl/tcp开销上保存任何内容 - 您只需大量增加帐单。 – 2012-07-31 05:33:33
请描述'不工作'。 – xdazz 2012-07-31 05:35:13