我需要把一个字符串,如打开字符串如果语句一个Java IF语句
class freud IF : 0.010<=cst0.1<=0.02^0.012<=cst0.2<=0.014^0.01<=cst0.3<=0.011^0.009<=cst0.4<=0.01^cst0.5=0.009^0.008<=cst0.6<=0.009^0.008<=cst0.7<=0.009^0.007<=cst0.8<=0.009^0.007<=cst0.9<=0.009^0.008<=cst1.0<=0.012
成实际的Java if语句:即
if(0.010 <= cst0.1 && cst0.1 <= 0.02 .....)
其中cst0.1成为名浮动等
任何想法?我已经尝试将字符串拆分为其组件,但是我需要的所有字符串都不相同!
感谢
你需要一个语法为您弗洛伊德IF语句。将其解析为AST,然后遍历该树以生成Java IF语句。 – duffymo 2012-08-17 09:10:50
字符串是否存在底层语法?你可能需要一个解析器。你可以看看JavaCC,但我听说它有一个陡峭的学习曲线。 – 2012-08-17 09:11:09
@SLBarth在使用'<=','='和teh属性(它是'cst0.1'等)的术语中有一个基础语法。但是就模式而言,您还可以获得一个字符串,如\t 'code'class freud IF:cst0.1 = 0.024^cst0.2 = 0.018^cst0.3 = 0.016^cst0.4 = 0.014^cst0.5 = 0.013^cst0.6 = 0.012^cst0.7 = 0.011^cst0 .8 = 0.011^cst0.9 = 0.01^cst1.0 = 0.013(1) – redrubia 2012-08-17 09:16:16