从一个表获取两个查询的重叠

下面的PHP/MySQL的代码工作，但它是笨重;两个查询，数据被转换成数组，数组进行比较！

（请注意这是一个功能，因为它返回是否有重叠）

$manager_sql = "SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND player_id = $mi"; 
$player_sql = "SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = $pi"; 

$manager_result = mysql_query($manager_sql) or die(mysql_error()); 
$manager_leagues = array(); 
while($sqlrow = mysql_fetch_array($manager_result)) { 
    extract($sqlrow); 
    $manager_leagues[] = $league_id; 
} 

$player_result = mysql_query($player_sql) or die(mysql_error()); 
$player_leagues = array(); 
while($sqlrow = mysql_fetch_array($player_result)) { 
    extract($sqlrow); 
    $player_leagues[] = $league_id; 
} 

$result = array_intersect($manager_leagues, $player_leagues); 

return count($result) > 0;

这里是在一个去做查询一些尝试：

(SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 2 AND player_id = '$mi') 
    UNION ALL 
(SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = '$pi')

看起来工作，但返回太多行：

SELECT league_id FROM league_members WHERE league_id IN (
    SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND player_id = '$mi' 
) AND league_id IN (
    SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = '$pi' 
)

来源

2013-02-27 sq2

通过重叠，你的意思是什么？ – 2013-02-27 05:59:08

如果你只是在第一个查询中检查'$ pi'，它会是同样的事情。 – kennypu 2013-02-27 06:02:03

A $ mi管理着一堆联赛（例如2,4,6），$ pi在一堆联赛中打球（例如1,3,7） - 重叠比较2,4,6和1,3， 7 – sq2 2013-02-27 06:06:27

尝试此查询：

$sql = "SELECT ls1.league_id FROM league_members AS ls1 
     INNER JOIN league_members AS ls2 ON ls1.league_id = ls2.league_id 
     WHERE ls1.manager = 1 AND ls1.member_active = 1 AND ls1.player_id = '".$mi."' 
     AND ls2.member_active = 1 AND ls2.player_id = '".$pi."'"

注：

mysql_ *函数deprectated，使用mysqli_ *函数或PDO
您的查询很容易受到SQL注入，使其seccure。

来源

2013-02-27 06:07:36

他的查询不一定是脆弱的，它取决于$ mi和$ pi的数据来自哪里。如果说，他们已经投到（int）s，那么注射应该不成问题。但我同意这是不好的做法。 – Jason 2013-02-27 06:13:09

感谢您的所有意见。 $ mi和$ pi只能是整数，因此安全。（着名的遗言） – sq2 2013-02-27 06:16:06

另一方面，仅仅因为你认为'$ mi'和'$ pi'只能是整数并不能实现，你必须执行这个约束。我说的是，你的应用程序今天可能还行，但随着时间的推移，你可能会将'$ mi'和'$ pi'的来源从现在改为不太可靠的来源，如果你避难在代码中明确强制实施整数约束，那么当时你可能会忘记这么做。 – Jason 2013-02-27 14:30:05

你希望找到任何league_id的同时具有$mi作为经理和$pi作为的球员之一？

SELECT DISTINCT l.league_id FROM league_members l JOIN league_members l2 ON l.league_id = l2.league_id AND l.member_active = 1 AND l2.member_active = 1 AND l.manager = 1 AND l2.manager = 0 WHERE l.player_id = $mi AND l2.player_id = $pi;

来源

2013-02-27 06:08:16 Jason

尝试

"SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND (player_id = '".$mi."' OR player_id = '".$pi."')";

来源

2013-02-27 06:08:47

请尝试以下将它的工作。如果没有，请让我知道你有哪些问题。

SELECT league_id FROM league_members WHERE league_id IN（ SELECT league_id FROM league_members WHERE（member_active = 1 AND（player_id = '$ MI' 或player_id = '$ PI'）和管理者= 1）

来源

2013-02-27 06:09:20

我明显没有“T试过，但我建议最后查询，与distinct关键字添加：

SELECT distinct league_id FROM league_members WHERE league_id IN (
    SELECT league_id FROM league_members WHERE manager = 1 AND member_active = 1 AND player_id = '$mi' 
) AND league_id IN (
    SELECT league_id FROM league_members WHERE member_active = 1 AND player_id = '$pi' 
)

来源

2013-02-27 06:11:23

这也适用 - 很高兴知道我离得很近！ – sq2 2013-02-27 06:15:25

这个怎么

SELECT league_id 
FROM league_members 
WHERE (manager = 1 AND member_active = 1 AND player_id = $mi) OR 
     (member_active = 1 AND player_id = $pi) 
GROUP BY league_id 
HAVING COUNT(*) = 2

来源

2013-02-27 06:18:36

此查询是否有效？ – 2013-02-27 06:20:26

从一个表获取两个查询的重叠

回答

相关问题