不能得到查询返回数据库中的所有数据

Question

<?php 
    define('HOST','localhost'); 
    define('USER','id2553362_hcoe'); 
    define('PASS','admin'); 
    define('DB','id2553362_hamrosadhan'); 

    $con = mysqli_connect(HOST,USER,PASS,DB) or die('Unable to Connect'); 

    $jsondata = file_get_contents("php://input"); 
    $data = json_decode($jsondata,true); 

    $bookeduser = $data['BookedUser']; 
    $bookfrom = $data['BookedFrom']; 
    $bookto = $data['BookTo']; 
    $category = $data['Category']; 
    $ulat = $data['ULat']; 
    $ulong = $data['ULong']; 


    $sql = "SELECT PostId,VehicleName,VechicleID,Category,Location, 
    Description,RateAmount, AvailableFrom,AvailableTo, (6371 * acos(cos( 
    radians($ulat)) * cos(radians(LocationLat)) * 
    cos(radians(LocationLong) - radians($ulong)) + 
    sin(radians($ulat))* 
    sin(radians(LocationLat)))) AS distance FROM VehicleDetails WHERE 
    Category='$category' AND AvailableFrom <= '$bookfrom' AND AvailableTo >= 
    '$bookto' HAVING distance < 500 "; 

    $query = mysqli_query($con, $sql) or die('query fails'); 




    if($query){ 
      while($vinfo = mysqli_fetch_array($query)) 
       { 

         var_dump($vinfo);die; 
       } 

    } 

    ?> 

我想我的代码返回表中的所有数据与查询过滤器，但我的查询只返回1数据。 输出：

       array(20) { 
    [0]=> 
    string(1) "3" 
    ["PostId"]=> 
    string(1) "3" 
    [1]=> 
    string(5) "cbras" 
    ["VehicleName"]=> 
    string(5) "cbras" 
    [2]=> 
    string(11) "ba56psa2437" 
    ["VechicleID"]=> 
    string(11) "ba56psa2437" 
    [3]=> 
    string(8) "2 wheels" 
    ["Category"]=> 
    string(8) "2 wheels" 
    [4]=> 
    string(7) "gongabu" 
    ["Location"]=> 
    string(7) "gongabu" 
    [5]=> 
    string(12) "got conditon" 
    ["Description"]=> 
    string(12) "got conditon" 
    [6]=> 
    string(4) "5000" 
    ["RateAmount"]=> 
    string(4) "5000" 
    [7]=> 
    string(10) "2017-09-15" 
    ["AvailableFrom"]=> 
    string(10) "2017-09-15" 
    [8]=> 
    string(10) "2017-10-15" 
    ["AvailableTo"]=> 
    string(10) "2017-10-15" 
    [9]=> 
    string(18) "0.8621561884069938" 
    ["distance"]=> 
    string(18) "0.8621561884069938" 
} 

this is my database

Answer 1

卸下模具;从while循环，并把它低于}

if($query){ 
    while($vinfo = mysqli_fetch_array($query)) { 

     var_dump($vinfo); 
    } 

    die(); 
}