2013-04-26 39 views
3

我有产生如下表的SQL查询,但我希望能够获得总对它们按类别分组的标列: enter image description here是否可以通过?计算组中列的总数?

这里是代码:

select pic.Name as Category, 
pis.Code as Code, 
pis.Name as Issue, 
count(it.ID) as 'total count', 
sum(mc.ots) as 'Imps', 
sum(case when ito.rating <50 then 1 else 0 end) as 'unfav count', 
sum(case when ito.Rating =50 then 1 else 0 end) as 'neu count', 
sum(case when ito.Rating >50 then 1 else 0 end) as 'fav count', 

(sum(case when ito.rating < 50 then 1.0 else 0.0 end)/count(it.ID) * 100) as 'unfav %', 
(sum(case when ito.Rating =50 then 1.0 else 0.0 end)/count(it.ID) * 100) as 'neu %', 
(sum(case when ito.Rating >50 then 1.0 else 0.0 end)/count(it.ID) * 100) as 'fav %', 

CONVERT(decimal(4,2),avg(ito.Rating)) as 'Av Rating %', 

count(it.id) * 100.0/sum(count(it.ID)) OVER() AS [% of Count], 
sum(mc.ots) * 100.0/sum(sum(mc.ots)) OVER() AS [% Imps] 

from 
Profiles P 
INNER JOIN ProfileResults PR ON P.ID = PR.ProfileID 
INNER JOIN Items it ON PR.ItemID = It.ID 
inner join Batches b on b.ID=it.BatchID 
left outer join BatchActionHistory bah on b.ID=bah.batchid 
inner join itemorganisations oit (nolock) on it.id=oit.itemid 
inner join itemorganisations ito (nolock) on it.id=ito.itemid 
inner join itemorganisationIssues ioi (nolock) on ito.id=ioi.itemorganisationid 
inner join ProjectIssues pis (nolock)on ioi.IssueID = pis.ID 
inner join ProjectIssueCategories pic (nolock)on pic.ID = pis.CategoryID 
inner join Lookup_ItemStatus lis (nolock) on lis.ID = it.StatusID 
inner join Lookup_BatchStatus lbs (nolock) on lbs.ID = b.StatusID 
inner join Lookup_BatchTypes bt on bt.id = b.Typeid 
inner join Lookup_MediaChannels mc on mc.id = it.MediaChannelID 


where p.ID = @profileID 
and b.StatusID IN (6,7) 
and bah.BatchActionID = 6 
and it.StatusID = 2 
and it.IsRelevant = 1 


Group BY pic.Name,pis.Name,pis.Code 
order by pic.name 

回答

4

您可以使用sum()窗口功能执行此操作。您实际上可以使用常规聚合功能来嵌套它。所以:

sum(count(it.ID)) over() as TotalCnt, 
sum(sum(mc.ots)) over() as TotalImps 

这假定您正在使用SQL Server 2005或更高版本。

这就是“整列”。对于一个小组,如亚历山大所指出的那样:亚历山大指出:

sum(count(it.ID))over(按类别划分)为CategoryCnt, sum(sum (mc.ots))(按分类划分)作为CategoryImps

+0

这个总和只是该组的总数或整个结果集? – Xerxes 2013-04-26 13:37:02

+1

@xerxes在回答建议由Gordon Linnhoff尝试添加OVER(PARTITION BY pis.Code) – 2013-04-26 14:01:06

+0

谢谢,它工作:) – Xerxes 2013-04-26 14:07:31

2

阅读关于WITH ROLLUP子句(或分组集,在SQL Server的更高版本中可用 - 我不知道你使用哪一个)。 它将按照组合GROUP BY(3列组,2列组,1列组和总计)的组合将输出分组。然后,您可以在聚合时使用GROUPING(column_name)= 1区分分组列。 希望这有助于。

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