如何将这两个对象与JavaScript关联？

Question

我有一个图像地图和一些复选框的一些地区。每个区域都有一个对应的复选框，我怎样才能做到这一点，当点击一个区域时，相应的复选框被勾选？

图像映射：

<%= image_tag("maps/mainmap.png", :width => "450", :height => "450", :class => "map", :usemap => "#mainmap", :alt => "") %> 

    <map name="mainmap"> 
    <area id="area-42" shape="poly" 
     coords="158,43,152,49,164,86,165,112,153,153,139,169,145,171,161,176,236,201,241,202,251,166,253,142,257,132,294,102,269,85,240,68,227,53,213,28,202,27" alt="North" 
     data-maphilight='{"stroke":false,"fillColor":"5F9EA0","fillOpacity":0.6}' 
     onmouseover="document.body.style.cursor='pointer'" 
     onmouseout="document.body.style.cursor='default'" > 

    <area id="area-43" shape="poly" 
     coords="296,103,258,133,254,143,252,166,242,203,263,209,272,204,322,226,340,250,360,241,356,230,357,222,378,214,395,195,394,188" alt="" 
     data-maphilight='{"stroke":false,"fillColor":"5F9EA0","fillOpacity":0.6}' 
     onmouseover="document.body.style.cursor='pointer'" 
     onmouseout="document.body.style.cursor='default'" >  
    </map>  

复选框：

<fieldset class="filter_form_fieldset areas"> 
    <% Area.all.each do |a| %> 
    <p class="area_check"><%= check_box_tag 'areas[]', a.id, false, :id => "area-#{a.id}" %> 
    <label for="area-<%= a.id %>"><p1><%= a.name %></p1></label></p> 
    <% end %> 
</fieldset> 

这会产生这样：

<img alt="" class="map" height="450" src="/assets/maps/mainmap.png" usemap="#mainmap" width="450" /> 

    <map name="mainmap"> 
    <area id="area-41" shape="poly" 
     coords="158,43,152,49,164,86,165,112,153,153,139,169,145,171,161,176,236,201,241,202,251,166,253,142,257,132,294,102,269,85,240,68,227,53,213,28,202,27" alt="North" 
     data-maphilight='{"stroke":false,"fillColor":"5F9EA0","fillOpacity":0.6}' 
     onmouseover="document.body.style.cursor='pointer'" 
     onmouseout="document.body.style.cursor='default'" > 

    <area id="area-42" shape="poly" 
     coords="296,103,258,133,254,143,252,166,242,203,263,209,272,204,322,226,340,250,360,241,356,230,357,222,378,214,395,195,394,188" alt="" 
     data-maphilight='{"stroke":false,"fillColor":"5F9EA0","fillOpacity":0.6}' 
     onmouseover="document.body.style.cursor='pointer'" 
     onmouseout="document.body.style.cursor='default'" >  
    </map> 

    <fieldset class="filter_form_fieldset areas"> 
     <p class="area_check"><input id="area-41" name="areas[]" type="checkbox" value="41" /> 
     <label for="area-41"><p1>Chinatown</p1></label></p> 
     <p class="area_check"><input id="area-42" name="areas[]" type="checkbox" value="42" /> 
     <label for="area-48"><p1>Village</p1></label></p> 
    </fieldset> 

我认为Java类的该位cript可能会将这两者联系起来，但它不起作用，关于我哪里出错的想法？

$(function() { 
    $('area').click(function(){ 
     var name = $(this).attr('id'); 
     var $checkbox = $('[id=' + id + ']'); 
     $checkbox.attr('checked', !$checkbox.attr('checked')); 
    });  
    }); 

非常感谢您的帮助！

Answer 1

您使用值在<area>标签和复选框中相同的ID。这将永远不会工作。您在获取$checkbox变量的过程中也遇到了一些错误。

我改变了<area>标签使用数据值和改变了代码检索数据的价值和现在的工作。你可以在这里看到它的行动：http://jsfiddle.net/jfriend00/ndwjC/。

因为我们没有实际的形象，一个有猜测应该点击哪里找热点，但是当你发现一个，就会切换的复选框。

HTML：

<img alt="" class="map" height="450" src="/assets/maps/mainmap.png" usemap="#mainmap" width="450" /> 

    <map name="mainmap"> 
    <area data-areanum="area-41" shape="poly" 
     coords="158,43,152,49,164,86,165,112,153,153,139,169,145,171,161,176,236,201,241,202,251,166,253,142,257,132,294,102,269,85,240,68,227,53,213,28,202,27" alt="North" 
     data-maphilight='{"stroke":false,"fillColor":"5F9EA0","fillOpacity":0.6}' 
     onmouseover="document.body.style.cursor='pointer'" 
     onmouseout="document.body.style.cursor='default'" > 

    <area data-areanum="area-42" shape="poly" 
     coords="296,103,258,133,254,143,252,166,242,203,263,209,272,204,322,226,340,250,360,241,356,230,357,222,378,214,395,195,394,188" alt="" 
     data-maphilight='{"stroke":false,"fillColor":"5F9EA0","fillOpacity":0.6}' 
     onmouseover="document.body.style.cursor='pointer'" 
     onmouseout="document.body.style.cursor='default'" >  
    </map> 

    <fieldset class="filter_form_fieldset areas"> 
     <p class="area_check"><input id="area-41" name="areas[]" type="checkbox" value="41" /> 
     <label for="area-41"><p1>Chinatown</p1></label></p> 
     <p class="area_check"><input id="area-42" name="areas[]" type="checkbox" value="42" /> 
     <label for="area-48"><p1>Village</p1></label></p> 
    </fieldset> 

的Javascript：

$(function() { 
    $('area').click(function(){ 
     var name = $(this).data("areanum"); 
     var $checkbox = $('#' + name); 
     $checkbox.attr('checked', !$checkbox.attr('checked')); 
    });  
    }); 

附：如果您使用的是最新的jQuery的版本，你应该使用.prop()改变复选框，而不是.attr()。