TASM将乘法结果作为ASCII符号输出，如何转换为整数

Question

该程序在TASM中制作的目的是将两个单位数字相乘并将结果写入屏幕。它实际上是乘以，但结果显示为ascii符号（我检查了这个网站http://chexed.com/ComputerTips/asciicodes.php和结果是正确的）。我不能让它显示结果为整数，特别是当结果是两位数字时。

 
.model small 
.stack
 

.data
 

msgA DB "Input 1st number: $" 
msgB DB 10, 13, "Input 2nd number $" 
msgC DB 10, 13, 10, 13, "Result: $" 
msgD DB 10, 13, 10, 13, "Error, retry", 10, 13, 10, 13, "$" 
 

.CODE
 

MOV AX，@DATA 
MOV DS，AX
 

jmp start 

num1 DB ? 
num2 DB ? 
result Dw ? 


start: 

    mov ah, 09    
    mov dx, offset msgA 
    int 21h 

    mov ah, 01 
    int 21h 
    mov num1, al 

    mov ah, 09 
    mov dx, offset msgB 
    int 21h 

    mov ah, 01 
    int 21h 
    mov num2, al 


    mov al,num1   
    sub al,'0' 
    mov bl,num2 
    sub bl,'0' 
    mul bl 
    add ax,'0' 

    mov result, ax 
    sub result, 48 

    mov ah, 09 
    mov dx, offset msgC 
    int 21h 

    mov ah, 02 
    mov dx, result 
    int 21h 

mov ax, 4c00h 
int 21h 
end 

Answer 1

你必须整数结果转换为字符串，其然后您可以使用int 21h/ah = 9进行打印。

做转换的简单方法如下（我会让你做翻译TASM语法x86汇编）：

ax = the value to convert 
si = &buffer[9];  // buffer is an array of at least 10 bytes 
buffer[9] = '$';  // DOS string terminator 
do { 
    ax /= 10; 
    si--;   // the buffer is filled from right to left 
    *si = dl + '0'; // place the remainder + '0' in the buffer 
} while (ax != 0); 
dx = si;    // dx now points to the first character of the string