如何使用PHP从字符串中删除子字符串？

Question

鉴于以下字符串

http://thedude.com/05/simons-cat-and-frog-100x100.jpg 

我想用substr或trim（或任何你找到更合适）返回此

http://thedude.com/05/simons-cat-and-frog.jpg 

也就是说，除去-100x100。我需要的所有图像都会在扩展名之前立即标记为文件名的末尾。

似乎有对此回应红宝石和Python，但不是PHP /特定于我的需要。

How to remove the left part of a string?

Remove n characters from a start of a string

Remove substring from the string

有什么建议？

Answer 1

如果你想匹配任何宽度/高度值：

$path = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg"; 

    // http://thedude.com/05/simons-cat-and-frog.jpg 
    echo preg_replace("/-\d+x\d+/", "", $path); 

演示：http://codepad.org/cnKum1kd

使用的模式是非常基本的：

/  Denotes the start of the pattern 
-  Literal - character 
\d+ A digit, 1 or more times 
x  Literal x character 
\d+ A digit, 1 or more times 
/ Denotes the end of the pattern

Answer 2

如果-100x100是您尝试从所有字符串中删除的唯一字符，为什么不使用str_replace？

$url = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg"; 
str_replace("-100x100", "", $url); 

Answer 3

$url = "http://thedude.com/05/simons-cat-and-frog-100x100.jpg"; 
$new_url = str_replace("-100x100","",$url); 

Answer 4

$url = str_replace("-100x100.jpg", '.jpg', $url); 

使用-100x100.jpg作为防弹解决方案。