计算表中的记录

Question

我想在txt框中显示countNum，但不显示任何内容。

我这样做。

<input type="text" value="<?php $countNum; ?>" disabled = "disabled"> 

<?php 
    $countNum = ""; 
    $Q = mysql_query("select * from blotterreport"); 

    while ($row = mysql_fetch_array($Q)) { 

     echo "<tr onclick='trClick()'>"; 
      echo "<td>" . $row["entrynumber"] . "</td>"; 
      echo "<td>" . $row["natureofcase"] . "</td>"; 
      echo "<td>" . $row["month"] . " " . $row["day"] . " " . $row["year"] . "</td>"; 
      echo "<td>" . $row["subject"] . "</td>"; 
     echo "</tr>"; 
     $countNum++; 
    } 
        echo $countNum; 
?> 

Answer 1

应该使用$countNum = mysql_num_rows($Q);前input文本字段。

<?php 
$Q = mysql_query("select * from blotterreport"); 
$countNum = mysql_num_rows($Q); 
?> 
<input type="text" value="<?php echo $countNum; ?>" disabled = "disabled"> 
<?php 
    while ($row = mysql_fetch_array($Q)) { 
     echo "<tr onclick='trClick()'>"; 
      echo "<td>" . $row["entrynumber"] . "</td>"; 
      echo "<td>" . $row["natureofcase"] . "</td>"; 
      echo "<td>" . $row["month"] . " " . $row["day"] . " " . $row["year"] . "</td>"; 
      echo "<td>" . $row["subject"] . "</td>"; 
     echo "</tr>"; 
    } 
?> 

注：请避免mysql_*功能，因为mysql_*功能已经从PHP 7.永久删除，请使用mysqli_或PDO。

对于PDO：http://php.net/manual/en/book.pdo.php

对于mysqli的：http://php.net/manual/en/mysqli.examples-basic.php