2
我有以下文件:除点符号还有其他方法吗?
{
"_id":ObjectId("4eb28bd60078621a7d0000aa"),
"metadata":{
"xuuid":{
"scope":"g",
"version":1,
"uuid":"0c1969c55b0241bfa3d37c6ceb900bba"
},
"custom":[
],
"file":{
"staticDataProviderId":4,
"contentType":"factsheet",
"name":"hugos tagebuch",
"size":2345,
"source":"bamldocuments",
"mimeType":"application/pdf",
"created":1319623020,
"modified":1319623020,
"accessed":1349623020,
"locales":[
"EN_us",
"CH_fr"
],
"countries":[
"CH"
],
"status":"published"
},
"links":[
{
"type":"instrument",
"key":5
},
{
"type":"instrument",
"key":3
}
]
},
"chunkSize":262144,
"length":14,
"md5":"2dd900d9be40e2dd3fc69cc77c14726c"
}
我可以通过下面的查询找到它:
db.fs.files.find({"metadata.links":{"type":"instrument","key":5}})
但我想有somtehing这样的(不符合我的文档等,原因在元数据键):
db.fs.files.find({"metadata"{"links":{"type":"instrument","key":5}}})
作为背景,在我的PHP代码我想拥有一个“查找”功能,得到一个标准只适用于在元数据中,所以我需要的东西不是很好,如:
public function find(array $criteria)
{
$extendedCriteria = array();
foreach($criteria as $key => $value) {
$extendedCriteria['metadata.'.$key => $value];
}
...
}
你能澄清吗?你想要第二个查询做什么?查找{“type”:“instrument”,“key”:5}是字段metadata.links中唯一的对象的记录? – chim