Ruby时间运行模块，睡眠时间为x秒

Question

我在学Ruby，遇到困难时刻Time。下面是从我需要通过rspec的要求：

it "takes about 1 second to run a block that sleeps for 1 second" do 
    elapsed_time = measure do 
    sleep 1 
    end 
    elapsed_time.should be_within(0.1).of(1) 
end 

我对measure代码：

def measure 
    start = Time.now 
    elapse = Time.now - start 
end 

我缺少什么？我无法通过睡觉1秒的街区。我试图测试和调用该块：

a = Proc.new{puts "hello"} 
sleep 1 
measure 

# => Unknown error 

Answer 1

要了解Ruby的代码块，我会建议你阅读this blog post。

你可以通过这个例子中看到：

def my_ordinary_method() 
    #do stuff 
    yield #the instruction that calls the block 
    #do more stuff 
end 

def the_caller() 
    #do stuff 
    my_ordinary_method() do 
    puts "I am the block. The one everyone talks about!" 
    puts "I am gentle, colorful and polite" 
    end 
end 

从上面的链接采取。

您的代码应该是这样的：

def measure 
    start = Time.now 
    yield if block_given? 
    elapse = Time.now - start 
end 

Answer 2

你错过了叫yield您的测量方法中：

def measure 
    start = Time.now 
    yield if block_given? 
    elapse = Time.now - start 
end