创建视图？

Question

目前我已经联接多个表一起一看，表设置以下列方式：

ACCOUNTS (id, first_name, last_name, etc.) 

CONTACTS (id, name, etc.) 

ACCOUNT_CONTACTS (id, account_id, contact_id) 

EMAIL_ADDR_BEAN_REL (id, bean_id (same as account_id/contact_id), email_address_id) 

EMAIL_ADDRESSES (email_address_id, email_address) 

但是我有两个表我一起加入这可以有一个ID相关联的多封邮件，在这里是结构的一个例子：

表：EMAIL_ADDR_BEAN_REL

id  email_address_id  bean_id 
1   2d5b8    61720 
2   14355b    61720 

表：EMAIL_ADDRESSES

id   email_address 
2db58  WalterWhite@gmail.com 
14355b  WW@gmail.com 

创建我的视图时，我希望能够检索这些与一个用户关联的多个电子邮件。目前，这是我认为的代码，只检索一个电子邮件：

SELECT AC.id, A.id AS account_id, A.name, A.description, A.industry, A.phone_fax, A.phone_office, A.shipping_address_street, A.shipping_address_city, A.shipping_address_state, A.shipping_address_postalcode, A.shipping_address_country, C.id AS contact_id, C.first_name, C.last_name, C.title, C.department, C.phone_home, C.phone_mobile, C.phone_work, C.primary_address_street, C.primary_address_city, C.primary_address_state, C.primary_address_postalcode, C.primary_address_country, EA.email_address, EA_C.email_address as email_contact 
FROM ACCOUNTS A 
INNER JOIN ACCOUNTS_CONTACTS AS AC ON A.id = AC.account_id 
INNER JOIN CONTACTS AS C ON C.id = AC.contact_id 
LEFT JOIN EMAIL_ADDR_BEAN_REL AS ER ON ER.bean_id = A.id 
AND ER.bean_module = "Accounts" 
LEFT JOIN EMAIL_ADDR_BEAN_REL AS ER_C ON ER_C.bean_id = C.id 
AND ER_C.bean_module = "Contacts" 
LEFT JOIN EMAIL_ADDRESSES AS EA ON ER.email_address_id = EA.id 
LEFT JOIN EMAIL_ADDRESSES AS EA_C ON ER_C.email_address_id = EA_C.id 

这个查询将返回与同用户相关联的两排，有除了电子邮件地址完全相同的信息，我想有第二个电子邮件地址（或其他电子邮件）添加到同一行，并没有创建额外的行。

帮助将不胜感激！

Answer 1

SELECT ... GROUP_CONCAT(email_address) ... 
    FROM ... 
    GROUP BY A.id;