我有一个递归函数来移动画布上的一些圆圈。内圈被放大(放大),所有其他圈被推开。 推动的圆圈推动其他圆圈等,直到缩放完成。JavaScript递归:超出最大调用堆栈大小
我得到一个错误“最大调用堆栈大小超过了”,我理解这个问题,但我只是不知道如何解决它... 我发现了三个可能的解决方案用于解决一般的递归问题:
- 更改递归进行迭代
- 使用memoization
- 使用的setTimeout
但我认为,我可以使用他们没有:
- 我无法实现,因为操作的未知数量需要反复
- 我不明白,记忆化不够好,但我认为它不适合或者(或也许我错了,有人可以告诉我)
- 我不能使用SetTimeout,因为它应该阻止在这个特定动画的函数调用。
如何解决此问题?
// Pushes circles aside when some other circle leans on these circles (on zoom in)
var moveCirclesAside = function(circle1, circleToSkip, groupOfMoves) {
var count = circles.length;
for (var i = 0; i < count; i++) {
// Skip the same circle
if (i == circle1.i) {
continue;
}
// Also skip the circle which was intended not to move any further
if (circleToSkip != null && i == circleToSkip.i) {
continue;
}
// Get second circle
var circle2 = circles[i];
// Calculate a distance between two circles
var dx = circle2.x - circle1.x;
var dy = circle2.y - circle1.y;
var distance = Math.sqrt((dx * dx) + (dy * dy));
// If circles already collided need to do some moving...
if (distance <= circle1.r + circle2.r + OD.config.circleSpacing) {
// Get collision angles
var angle = Math.atan2(dy, dx);
var sine = Math.sin(angle);
var cosine = Math.cos(angle);
// Some circle position calculation
var x = OD.config.circleSpacing;
var xb = x + (circle1.r + circle2.r);
var yb = dy * cosine - dx * sine;
// Save each state (move) of any circle to the stack for later rollback of the movement
groupOfMoves.push(copyCircleByVal(circle2));
// Move the circle
circle2.x = circle1.x + (xb * cosine - yb * sine);
circle2.y = circle1.y + (yb * cosine + xb * sine);
// Make sure that circle won't go anywhere out of the canvas
adjustCircleByBoundary(circle2);
// If moved circle leans against some other circles make sure that they are moved accordingly
// And such related moves must be grouped for correct rolback of moves later - so we pass 'groupOfMoves' var
moveCirclesAside(circle2, circle1, groupOfMoves);
}
}
};
您的回答也很有帮助,但可悲的是我只能接受一个答案......谢谢! – fizis 2012-02-29 13:35:32
我已经为你表达了这种感悟。 – agm1984 2017-11-12 21:07:11