如何从列SQL Server分析xml

Question

我安装了SQL Server 2012。有一个名为channel_group的表格，其中有多个记录。

[dbo].[CHANNEL_GROUP] 
(
    [ID] [nvarchar](255) NOT NULL, 
    [NAME] [nvarchar](255) NOT NULL, 
    [REVISION] [int] NULL, 
    [CHANNEL_GROUP] [nvarchar](max) NULL 
) 

从CHANNEL_GROUP专栏中，我需要得到的ID标签的所有值与数据库中的每个记录每个通道标记每个记录。

什么是解析这个或查询我可以运行的最好方法是动态的？

<channelGroup version="3.4.2"> 
     <id>990b417d-27ae-4928-b4cc-cc010665615e</id> 
     <name>Production</name> 
     <revision>3</revision> 
     <lastModified> 
      <time>1490385251147</time> 
      <timezone>America/New_York</timezone> 
     </lastModified> 
     <description></description> 
     <channels> 
      <channel version="3.4.2"> 
       <id>321439ff-46d6-4c3d-b1cd-ebc48d3c7fd2</id> 
       <enabled>false</enabled> 
       <revision>0</revision> 
      </channel> 
      <channel version="3.4.2"> 
       <id>c2d06aee-3031-4c6a-a3c1-23f7e96c971c</id> 
       <enabled>false</enabled> 
       <revision>0</revision> 
      </channel> 
     </channels> 
</channelGroup> 

Answer 1

Declare @YourTable table (ID int,CHANNEL_GROUP varchar(max)) 
Insert Into @YourTable values 
(1,'<channelGroup version="3.4.2"><id>990b417d-27ae-4928-b4cc-cc010665615e</id><name>Production</name><revision>3</revision><lastModified><time>1490385251147</time><timezone>America/New_York</timezone></lastModified><description></description><channels><channel version="3.4.2"><id>321439ff-46d6-4c3d-b1cd-ebc48d3c7fd2</id><enabled>false</enabled><revision>0</revision></channel><channel version="3.4.2"><id>c2d06aee-3031-4c6a-a3c1-23f7e96c971c</id><enabled>false</enabled><revision>0</revision></channel></channels></channelGroup>'), 
(2,'<channelGroup version="3.9.9"><id>990b417d-27ae-4928-b4cc-cc010665615e</id><name>Production</name><revision>3</revision><lastModified><time>1490385251147</time><timezone>America/New_York</timezone></lastModified><description></description><channels><channel version="3.4.2"><id>SomeOtherID</id><enabled>false</enabled><revision>0</revision></channel><channel version="3.4.2"><id>AnotherID</id><enabled>false</enabled><revision>0</revision></channel></channels></channelGroup>') 

Select A.ID 
     ,Channel_ID= C.ID 
From @YourTable A 
Cross Apply (Select XMLData=cast(A.CHANNEL_GROUP as xml)) B 
Cross Apply (
       Select [id]  = f.n.value('(id)[1]','varchar(50)') 
       From B.XMLData.nodes('channelGroup/channels') t(n) 
       Cross Apply t.n.nodes('channel') f(n) 
      ) C 

返回

ID Channel_ID 
1 321439ff-46d6-4c3d-b1cd-ebc48d3c7fd2 
1 c2d06aee-3031-4c6a-a3c1-23f7e96c971c 
2 SomeOtherID 
2 AnotherID