从javascript传递数组对象到php

Question

所以我构建了一个传递给PHP的对象数组，但我想知道这是传递它们的最简洁的方法，并且将是PHP中最容易处理的方法。

我的部分组件数量是基于我的谷歌地图反向地理编码器返回的变量而被部分抛弃。

每个小组将被插入作为一个单独的一行到MySQL用“名”和“类型”

var neighborhood = extractLongFromAddress(results[0].address_components, "sublocality"); 
var town = extractLongFromAddress(results[0].address_components, "locality"); 
var stateShort = extractShortFromAddress(results[0].address_components, "administrative_area_level_1"); 
var stateLong = extractLongFromAddress(results[0].address_components, "administrative_area_level_1"); 
var country = extractLongFromAddress(results[0].address_components, "country"); 

var groups=[]; 
if(town && stateShort){ 
    groups.push({name: town+", "+stateShort, 
      type:"city" 
    }); 
} 

if(neighborhood && stateLong){ 
    groups.push({name: neighborhood+", "+stateShort, 
      type:"neighborhood" 
    }); 
} 

if(stateLong){ 
    groups.push({name:stateLong, 
      type:"state" 
    }); 
} 

if(country){ 
    groups.push({name:country, 
      type:"country" 
    }); 
} 
console.log(groups); 

真诚的感谢所有帮助的参数。非常感谢。

Answer 1

只需将数组转换为JSON字符串JSON.stringify()并发送给php;在PHP你会做json_decode()