我想制作一个程序,从用户输入中获取一天,然后告诉他们前一天和后一天。用户还应该能够输入要添加的日期和程序应该在当天输出。星期几
例如用户输入1 =星期一,明天是= 2星期二昨天= 3周日
如果用户其星期一(1),并增加了12天输出应为星期六(6)
的说问题是无论何时“theWeekDay”大于7,它都不会输出,因为TheDay();没有超过7的条件。请帮助我!
非常感谢你!
import java.util.Scanner;
import java.util.Scanner;
public class Problem_3 {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int theWeekDay;
System.out.println("What Day Is It?");
theWeekDay = input.nextInt();
Days one = new Days(theWeekDay);
System.out.println("Today It Is: ");
one.TheDay(theWeekDay);
System.out.println("Yesterday It Was: ");
one.PreviousDay(theWeekDay);
System.out.println("Tomorrow It Is: ");
one.NextDay(theWeekDay);
System.out.println("How Many Days To Add?");
int x = input.nextInt();
System.out.println("Now It Is: ");
one.AddedDays(x);
}
}
class Days {
private int theWeekDay;
public Days(int theWeekDay) {
this.theWeekDay = theWeekDay;
}
public int getTheWeekDay() {
return theWeekDay;
}
public void setTheWeekDay(int theWeekDay) {
this.theWeekDay = theWeekDay;
}
public int TheDay(int theWeekDay) {
// an arra days of week + then add days in it
if (theWeekDay == 0) {
theWeekDay = theWeekDay + 7;
}
if (theWeekDay == 1) {
System.out.println("Monday");
} else if (theWeekDay == 2) {
System.out.println("Tuesday");
} else if (theWeekDay == 3) {
System.out.println("Wednsday");
} else if (theWeekDay == 4) {
System.out.println("Thursday");
} else if (theWeekDay == 5) {
System.out.println("Friday");
} else if (theWeekDay == 6) {
System.out.println("Saturday");
} else if (theWeekDay == 7) {
System.out.println("Sunday");
}
return theWeekDay;
}
public int PreviousDay(int theWeekDay) {
theWeekDay = theWeekDay - 1;
return TheDay(theWeekDay);
}
public int NextDay(int theWeekDay) {
theWeekDay = theWeekDay + 1;
if (theWeekDay > 7) {
theWeekDay = 1;
}
return TheDay(theWeekDay);
}
public int AddedDays(int AddedDays) {
getTheWeekDay();
theWeekDay = theWeekDay + AddedDays;
return TheDay(theWeekDay);
}
}
如果'theWeekDay'> 7,你希望发生什么? –
当有人输入12时,你的函数应该如何知道它应该从哪一天开始? –