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我正在使用RxCPP,并且难以理解其行为。RxCPP行为不同于Rx.Net
这里有两个程序,一个在Rx.Net中,另一个在RxCPP中。 他们假设输出相同的照片,但他们不。
该程序从鼠标流中获取点数,并计算点之间的三角洲流。
鼠标是一串流的点,每一笔 - 从下往上按是一个流。老鼠一个接一个地给这些流。
在这些试验中的期望的输出是:
德尔塔无0:0,0
德尔塔无1:5,0
德尔塔无2是:0,5
德尔塔无3是:2,3
这是Rx.Net输出的内容。
Rx.Cpp只输出第一行:Delta no 0是:0,0
任何想法?
Rx.Cpp例如:
#include <rx.hpp>
namespace rx = rxcpp;
namespace rxsub = rxcpp::subjects;
using rxob = rx::observable<>;
struct Point
{
Point(int x, int y) : x(x), y(y) {}
int x = 0, y = 0;
Point operator-() const { return {-x, -y}; }
Point operator+(const Point& other) const { return Point{x + other.x, y + other.y}; }
Point operator-(const Point& other) const { return operator+(-other); }
};
std::ostream& operator<<(std::ostream& o, const Point& p)
{
return o << "(" << p.x << ", " << p.y << ")";
}
void TestRxCPP()
{
using RxPoint = rx::observable<Point>;
using Strokes = rx::observable<RxPoint>;
using StrokesSubject = rxsub::subject<RxPoint>;
StrokesSubject mouseSource;
auto strokes = mouseSource.get_observable();
auto deltaVectors = [](Strokes strokes) {
auto deltas = strokes.flat_map([=](RxPoint stroke) {
auto points = stroke;
// create stream of delta vectors from start point
auto firstPoint = points.take(1);
auto delta =
points.combine_latest([](Point v0, Point v1) { return v0 - v1; }, firstPoint);
return delta;
});
return deltas;
};
auto delta = deltaVectors(strokes);
int n = 0;
delta.subscribe(
[&](const Point& d) { std::cout << "Delta no. " << n++ << " is: " << d << std::endl; });
auto testMouse = rxob::from(Point{3 + 0, 4 + 0}, Point{3 + 5, 4 + 0}, Point{3 + 0, 4 + 5}, Point{3 + 2, 4 + 3});
mouseSource.get_subscriber().on_next(testMouse);
}
Rx.Net例如:
void RxNET()
{
var strokesS = new Subject<IObservable<Point>>();
Func<IObservable<IObservable<Point>>, IObservable<Point>>
deltaVectors = strokes =>
{
var deltas = strokes.SelectMany(stroke =>
{
var points = stroke;
// create stream of delta vectors from start point
var firstPoint = points.Take(1);
var deltaP =
points.CombineLatest(firstPoint, (v0, v1) => new Point(v0.X - v1.X, v0.Y - v1.Y));
return deltaP;
});
return deltas;
};
var delta = deltaVectors(strokesS);
var n = 0;
delta.Subscribe(d => { Console.WriteLine($"Delta no {n++} is: {d}\n"); });
var testMouse = new List<Point>
{
new Point(3 + 0, 4 + 0),
new Point(3 + 5, 4 + 0),
new Point(3 + 0, 4 + 5),
new Point(3 + 2, 4 + 3)
}.ToObservable();
strokesS.OnNext(testMouse);
}
您是否尝试过使用调试器或包括跟踪语句找出的功能将两片岔开
冷热源是否行得通呢? –
它很难(对我来说)调试rxcpp库,它的非常高端的C++ :-( – ShaulF