问题隐藏zlib压缩基地64字符串Uiimage

Question

在我目前的项目中，我不得不解析base 64字符串，这是由flex（Adobe Flash）应用程序编码和存储。通过与flex开发团队讨论，我发现他们以位图格式存储图像字符串，所以我认为它是一个像素表示。

因此，我的第一个问题是，在上述情况下，我可以直接将原始数据转换为使用base64解码类的UIimage，或者我必须使用CGBitmapContext？

但是，目前我已经实现了下面提到的转换代码。

` //转换为Base64数据

NSData *decodedData = [QSStrings decodeBase64WithString:_settingSerializedImage.currentValue]; 


NSError *error = nil; 
NSData *unCompressedData = [decodedData bbs_dataByInflatingWithError:&error]; 



NSData *dataImage = [NSMutableData new]; 
NSUInteger bytePosition = 0; 
uint8_t * bytes = malloc(5); 
[unCompressedData getBytes:&bytes range:NSMakeRange(unCompressedData.length-3, 3)]; 

bytes = OSSwapBigToHostInt16(bytes); 
int width = (int)bytes; 

[unCompressedData getBytes:&bytes range:NSMakeRange(unCompressedData.length-5, 5)]; 

bytes = OSSwapBigToHostInt16(bytes);dataImage = [unCompressedData subdataWithRange:NSMakeRange(0, (unCompressedData.length -5))]; 

NSUInteger length = [dataImage length]; 
unsigned char *bytesData = malloc(length * sizeof(unsigned char)); [dataImage getBytes:bytesData length:length];UIImage *imgScreenShot = [ScreenshotPortlet convertBitmapRGBA8ToUIImage:bytesData withWidth:width withHeight:height];` 

下面

是用于使用核心图形

+ (UIImage *) convertBitmapRGBA8ToUIImage:(unsigned char *) buffer 
          withWidth:(int) width 
          withHeight:(int) height { 

char* rgba = (char*)malloc(width*height*4); 
for(int i=0; i < width*height; ++i) { 
    rgba[4*i] = buffer[4*i]; 
    rgba[4*i+1] = buffer[4*i+1]; 
    rgba[4*i+2] = buffer[4*i+2]; 
    rgba[4*i+3] = buffer[4*i+3]; 
} 
// 


size_t bufferLength = width * height * 4; 
CGDataProviderRef provider = CGDataProviderCreateWithData(NULL, rgba, bufferLength, NULL); 
size_t bitsPerComponent = 8; 
size_t bitsPerPixel = 32; 
size_t bytesPerRow = 4 * width; 

CGColorSpaceRef colorSpaceRef = CGColorSpaceCreateDeviceRGB(); 
    if(colorSpaceRef == NULL) { 
    NSLog(@"Error allocating color space"); 
    CGDataProviderRelease(provider); 
    return nil; 
} 

CGBitmapInfo bitmapInfo = kCGBitmapByteOrder32Big | kCGImageAlphaPremultipliedFirst; 

CGColorRenderingIntent renderingIntent = kCGRenderingIntentDefault; 
CGImageRef iref = CGImageCreate(width, 
           height, 
           bitsPerComponent, 
           bitsPerPixel, 
           bytesPerRow, 
           colorSpaceRef, 
           bitmapInfo, 
           provider, 
           NULL, 
           YES, 
           renderingIntent); 

uint32_t* pixels = (uint32_t*)malloc(bufferLength); 

if(pixels == NULL) { 
    NSLog(@"Error: Memory not allocated for bitmap"); 
    CGDataProviderRelease(provider); 
    CGColorSpaceRelease(colorSpaceRef); 
    CGImageRelease(iref); 
    return nil; 
} 

CGContextRef context = CGBitmapContextCreate(pixels, 
              width, 
              height, 
              bitsPerComponent, 
              bytesPerRow, 
              colorSpaceRef, 
              bitmapInfo); 

if(context == NULL) { 
    NSLog(@"Error context not created"); 
    free(pixels); 
} 

UIImage *image = nil; 
if(context) { 

    CGContextDrawImage(context, CGRectMake(0.0f, 0.0f, width, height), iref); 

    CGImageRef imageRef = CGBitmapContextCreateImage(context); 

    image = [UIImage imageWithCGImage:imageRef]; 

    CGImageRelease(imageRef); 
    CGContextRelease(context); 
} 

CGColorSpaceRelease(colorSpaceRef); 
CGImageRelease(iref); 
CGDataProviderRelease(provider); 


if(pixels) { 
    free(pixels); 
} 
return image; 

}

Here is the output I'm getting , a distorted image :

因此，在图像转换的原始数据的方法任何人都可以提出更好的解决方案离子还是告诉我是否在正确的方向？谢谢，提前:)

仅供参考here你可以找到原来的基地64串

Answer 1

图像转换为base64string：

- (NSString *)imageToNSString:(UIImage *)image 
{ 
    NSData *data = UIImagePNGRepresentation(image); 

    return [data base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed]; 
} 

要转换base64string图像：

- (UIImage *)stringToUIImage:(NSString *)string 
{ 
    NSData *data = [[NSData alloc]initWithBase64EncodedString:string options:NSDataBase64DecodingIgnoreUnknownCharacters]; 

    return [UIImage imageWithData:data]; 
}