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这是我的登录应用程序连接到SQL Server的代码。为什么此登录代码在语法错误时编译失败？
package com.helpdesk.loginapplication;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.content.Intent;
import android.net.ParseException;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
public class Main extends Activity
{
JSONArray jArray;
String result = null;
InputStream is = null;
StringBuilder sb=null;
public static final String LOG_TAG="HI..";
EditText un,pw;
TextView error;
Button ok;
int flag=0;
public static String name;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
un=(EditText)findViewById(R.id.et_un);
pw=(EditText)findViewById(R.id.et_pw);
ok=(Button)findViewById(R.id.btn_login);
error=(TextView)findViewById(R.id.tv_error);
ok.setOnClickListener(new View.OnClickListener()
{
public void onClick(final View v)
{
// create a new thread for httppost request
new Thread()
{
public void run()
{
ArrayList<namevaluepair> nameValuePairs = new ArrayList<namevaluepair>();
//http post
try
{
String nm=un.getText().toString();
String pwd=pw.getText().toString();
HttpClient httpclient = new DefaultHttpClient();
//provide the values to asp.net script through query string
String qs="http://192.168.1.162/LoginApp/LoginApp/Default.aspx?userName="+nm+"&password="+pwd;
HttpPost httppost = new HttpPost(qs);
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}
catch(Exception e)
{ Log.e("log_tag", "Error in http connection"+e.toString()); }
//convert response to string
try
{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null){
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
try
{
jArray = new JSONArray(result);
JSONObject json_data=null;
for(int i=0;i<jArray.length();i++)
{
flag=1;
json_data = jArray.getJSONObject(i);
name=json_data.getString("name");
String pwd=json_data.getString("password");
// get values from database and show on logcat view
//for invalid user, the values are null
Log.v(LOG_TAG,"name :"+name);
Log.v(LOG_TAG,"password :"+pwd);
}
if(flag==0)
{
//create new thread derived from “runOnUiThread” class to connect with View
// bcz simple Thread class can’t access View
LoginApplicationActivity.this.runOnUiThread(new Runnable()
{
public void run() {
error.setText("Invalid User...");
//Toast.makeText(LoginApplicationActivity.this, "Invalid
//Login,"Toast.LENGTH_LONG).show();
}
});
}
else{
Log.v("LOG-TAG","valid");
LoginApplicationActivity.this.runOnUiThread(new Runnable() {
public void run() {
error.setText("Login successful....");
// Toast.makeText(LoginApplicationActivity.this, "Login Successful",
//Toast.LENGTH_LONG).show();
//for valid user, start another activity “ULogin” which says ‘hello’ to user..
Intent myIntent = new Intent(v.getContext(), Ulogin.class);
startActivityForResult(myIntent, 0);
}
});
}
}
catch(JSONException e1){
Toast.makeText(getBaseContext(), "error" ,Toast.LENGTH_LONG).show();
}catch (ParseException e1) {
e1.printStackTrace();
}finally {});
}
}
此代码在“finally”行产生错误。
Syntax error, insert "}" to complete ClassBody Main.java line 138 Java Problem
Syntax error, insert "}" to complete MethodBody Main.java line 138 Java Problem
Syntax error, insert ";" to complete Statement Main.java line 138 Java Problem
Syntax error, insert "}" to complete ClassBody Main.java line 138 Java Problem
Syntax error, insert "}" to complete MethodBody Main.java line 138 Java Problem
我该如何解决这个问题？
你在这里做了什么样的编码？你已经在'onClick'里面编写了完整的代码。你在代码中的某个地方缺少'}'。 – GrIsHu
@Nor atika Salleh在'finally'附近删除'}'。 – Ram
@Nor atika Salleh你在行尾添加了额外的'}'，并且在'finally'块中移除'''''代码块的错误末尾。看看我的答案。 – GrIsHu