为什么zope.interface.Interface的子类的子类不会继承其父母名称？

Question

例子：

>>> from zope.interface import Interface, Attribute 
>>> class IA(Interface): 
... foo = Attribute("foo") 
... 
>>> IA.names() 
['foo'] 
>>> class IB(IA): 
... bar = Attribute("bar") 
... 
>>> IB.names() 
['bar'] 

我怎么能有IB.names（）返回在IA定义以及属性？

Answer 1

如果你看看zope.interface.interfaces module你会发现Interface类有IInterface interface definition！它记录了names方法如下：

def names(all=False): 
    """Get the interface attribute names 

    Return a sequence of the names of the attributes, including 
    methods, included in the interface definition. 

    Normally, only directly defined attributes are included. If 
    a true positional or keyword argument is given, then 
    attributes defined by base classes will be included. 
    """ 

要从而扩大你的例子：

>>> from zope.interface import Interface, Attribute 
>>> class IA(Interface): 
...  foo = Attribute("foo") 
... 
>>> IA.names() 
['foo'] 
>>> class IB(IA): 
...  bar = Attribute("bar") 
... 
>>> IB.names() 
['bar'] 
>>> IB.names(all=True) 
['foo', 'bar'] 

Answer 2

明白了：

IB.names(all=True) 

我想我应该在今后的检查方法签名的详细。