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我想垂直显示表。现在，它横向显示。每个 和每个字段都显示。我如何垂直显示表格？ 还有一件事我想添加一个更多的功能按钮。当前 日期加入到数据库按钮被点击时 提交。现在，这段代码使得我的状态为0，并且不更新数据库中的日期 。显示表格垂直
<html>
<head>
<meta name="description" content="website description" />
<meta name="keywords" content="website keywords, website keywords" />
<meta http-equiv="content-type" content="text/html; charset=windows-
1252" />
<link rel="stylesheet" type="text/css" href="style/style.css" />
<style>
<table>
{
border-style:solid;
border-width:2px;
border-color:pink;
}
</style>
</head>
<?php
include 'inc/head.php';
include 'connection.php';
$id = $_GET['id'];
$sql = "SELECT * FROM user WHERE id='$id'";
$query = mysqli_query($conn, $sql);
echo "<table border='6'>
<tr>
<th>Application Type</th> <br>
<th>First name</th><br>
<th>Sur name</th><br>
<th>title</th>
<th>Date of Birth</th>
<th>Gender</th>
<th>Nationality</th>
<th>Country of Birth</th>
<th>Applicant's Location</th>
<th>alias</th>
<th>Criminal </th>
<th>Country of passport</th>
<th>Passport number</th>
<th>Passport issue date </th>
<th>Passport expiry date</th>
<th>Address </th>
<th>City</th>
<th>State</th>
<th>Postal Code</th>
<th>Country</th>
<th>Email Address</th>
<th>Home Number</th>
<th>Business Number</th>
<th>mobile</th>
</tr>";
while($row = mysqli_fetch_assoc($query)) {
echo "<tr>";
echo " <td>" . $row['applicationtype'] . "</td>";
echo " <td>" . $row['firstname'] . "</td>";
echo " <td>" . $row['lastname'] . "</td>";
echo " <td>" . $row['title1'] . "</td>";
echo " <td>" . $row['dob'] . "</td>";
echo " <td>" . $row['gender'] . "</td>";
echo " <td>" . $row['nationality'] . "</td>";
echo " <td>" . $row['countryofbirth'] . "</td>";
echo " <td>" . $row['applicantlocation'] . "</td>";
echo " <td>" . $row['alias'] . "</td>";
echo " <td>" . $row['criminal'] . "</td>";
echo " <td>" . $row['countryofpassport'] . "</td>";
echo " <td>" . $row['passportnumber'] . "</td>";
echo " <td>" . $row['pid'] . "</td>";
echo " <td>" . $row['ped'] . "</td>";
echo " <td>" . $row['address'] . "</td>";
echo " <td>" . $row['city'] . "</td>";
echo " <td>" . $row['state'] . "</td>";
echo " <td>" . $row['postalcode'] . "</td>";
echo " <td>" . $row['country'] . "</td>";
echo " <td>" . $row['email'] . "</td>";
echo " <td>" . $row['homephone'] . "</td>";
echo " <td>" . $row['businessphone'] . "</td>";
echo " <td>" . $row['mobile'] . "</td>";
echo "</tr>";
}
echo "</table><br><br>";
if(isset($_POST['submit'])) {
echo $radio = $_POST['radio'];
$date_clicked = date('Y-m-d H:i:s');
$sql = "UPDATE user SET visastatus='$radio' AND currentdate='$date_clicked' WHERE id='$id'";
$query = mysqli_query($conn, $sql);
if($query) {
echo "<h4 style='color:green'>Action Performed Successfully....</h4>";
} else {
echo "<h4 style='color:red'>Failed.</h4>";
}
}
?>
<form method="POST" action="" enctype="multipart/form-data">
<div class="col-xs-12 col-sm-6 col-md-6 col-lg-6" style="margin-top:
8px;">
<label class="checkbox-inline tourist-rad">
<input type="radio" name="radio" id="success"
value="Successfull">Successfull
</label>
<label class="checkbox-inline tourist-rad">
<input type="radio" name="radio" id="decline" value="Declined">Declined
</label>
</div>
<div class="form-group">
<button type="submit" name="submit" value="submit" class="btn btn-
primary" style="float: right;">Update Menu Item</button>
</div>
</body>
</html>
一些明智的代码缩进将是一个不错的主意。 它可以帮助我们阅读代码，更重要的是它可以帮助您调试代码**。 – GrumpyCrouton
[小博]（http://bobby-tables.com/）说** [你是在对SQL注入攻击的风险（https://stackoverflow.com/q/60174/）**。了解[MySQLi]（http://php.net/manual/en/mysqli.quickstart.prepared-statements.php）的[Prepared Statements]（准备语句）（https://en.wikipedia.org/wiki/Prepared_statement）。即使** [转义字符串]（https://stackoverflow.com/q/5741187）**是不安全的！我推荐'PDO'，我[写了一个函数]（http://paragoncds.com/grumpy/pdoquery/#function），使它非常容易**，非常干净**，以及更多**安全**比使用非参数化查询。 – GrumpyCrouton
要显示垂直，你可以使用transform：rotate（90deg）;如果这是你想要的。 –