与递归函数替换for循环

Question

我就简单的js函数的工作... u能告诉我如何替换递归函数的循环.. 在拨弄下面提供我的代码.. 我想学习JS

http://jsfiddle.net/utbsgnzu/4/

function operation() { 
    console.log("testing"); 
} 

function repeat(operation, num) { 
    for (var i = 0; i < num; i++) { 
     operation(); 
    } 
} 

//repeat(operation, 10); 
module.exports = repeat 

Answer 1

function operation() { 
    console.log("testing"); 
} 

function repeat(operation, num) { 
    if (num === 0) return; 
    operation(); 
    repeat(operation, num-1); 
} 

//repeat(operation, 10); 
module.exports = repeat 

Answer 2

循环是自然迭代。递归方法并不适合这种情况。无论如何，在这里你走了。但用它只是为了好玩，从来没有真正:)

function repeat(func,maxruns,run){ 
    if(run>=maxruns){ 
     return; 
    } 
    func(); 
    repeat(func,maxruns,(run||0)+1); 
} 
repeat(operation,10); 

Answer 3

var foo = function foo() { 
console.log(arguments.callee); // logs foo() 
// callee could be used to invoke recursively the foo function (e.g.  arguments.callee()) 
}(); 
</script></body></html>