2012-02-07 63 views
0

我想对数组进行排序,以便我可以基于一个参数(它们的电子邮件地址)从多维数组中抽取一些用户。最终我希望将原始数组分成两个不同的数组:一个使用选定的电子邮件地址(下面标记为$js)和一个不是(下面标记为$not_js)。使用PHP从多维数组中查找/排序多个值

这里是我的我的代码:

<?php 
$users['1'] = array('name'=>'bob barker', 
       'email'=>'[email protected]', 
        'id'=>'1'); 

$users['2'] = array('name'=>'jerry jones', 
       'email'=> '[email protected]', 
        'id'=>'2'); 

$users['3'] = array('name'=>'sue smith', 
       'email'=>'[email protected]', 
        'id'=>'3'); 

$users['4'] = array('name'=>'zach zed', 
       'email'=>'[email protected]', 
        'id'=>'4'); 

function sort_jerry_and_sue($users) 
{ 
    $j_and_s=array('[email protected]', '[email protected]'); 
    $not_js=array(); 
    foreach($j_and_s as $row=>$js){ 
      if(in_array($js, $users)){ 
      } 
      else { 
       array_push($not_js, $users); 
      } 
    } 
    return $not_js; 
} 

$not_js = array_filter($users, 'sort_jerry_and_sue'); 

print_r($not_js); 
// this is what i'd like it to print=> $not_js = Array ([0] => Array ([name] => bob barker [email] => [email protected] [id] => 1) [1] => Array ([name] => zach zed [email] => [email protected] [id] => 4)) 
print_r($js); 
// this is what i'd like it to print=> $js = Array ([0] => Array ([name] => jerry jones [email] => [email protected] [id] => 2) [1] => Array ([name] => sue smith [email] => [email protected] [id] => 3)) 
?> 

目前印刷$not_js返回所有4个用户和$js没有打印任何东西所以很明显这是不正确的。任何想法将不胜感激!

回答

1

我认为你会以这种错误的方式去做。 array_filter就像是一个array_map调用,它将第二个参数作为可调用对象,它将返回一个布尔值,以确定该值是否存在于已过滤的集合中。 sort_jerry_and_sue函数的参数将是$users数组中的每个用户元素,它们是一个接一个。

通过返回false,如果用户有一个预定义的电子邮件地址,你基本上将它们从结果数组中排除。

一旦您有一组布尔过滤集合,您可以通过执行array_diff_assoc来获得不同的赞美。

<?php 


class EmailFilter { 

    private $emails = array(); 

    public function __construct(array $emails) { 
    $this->emails = $emails; 
    } 

    public function filter_users($user) { 
    return in_array($user['email'], $this->emails); 
    } 

} 

$users['1'] = array('name'=>'bob barker', 'email'=>'[email protected]', 'id'=>'1'); 
$users['2'] = array('name'=>'jerry jones', 'email'=> '[email protected]', 'id'=>'2'); 
$users['3'] = array('name'=>'sue smith', 'email'=>'[email protected]', 'id'=>'3'); 
$users['4'] = array('name'=>'zach zed', 'email'=>'[email protected]', 'id'=>'4'); 

$filter_emails = array('[email protected]', '[email protected]'); 
$not_js = array_filter($users, array(new EmailFilter($filter_emails), 'filter_users')); 
$js = array_diff_assoc($users, $not_js); 

// this is what i'd like it to print=> $not_js = Array ([0] => Array ([name] => bob barker [email] => [email protected] [id] => 1) [1] => Array ([name] => zach zed [email] => [email protected] [id] => 4)) 
print_r($not_js); 
// this is what i'd like it to print=> $js = Array ([0] => Array ([name] => jerry jones [email] => [email protected] [id] => 2) [1] => Array ([name] => sue smith [email] => [email protected] [id] => 3)) 
print_r($js); 
?> 
+0

我喜欢你更好:) – bobsoap 2012-02-07 04:13:57

+0

真棒sberry!非常感谢! -tim – 2012-02-07 04:16:16

+0

sberry,还有一个问题:我如何将sort_jerry_and_sue()函数之外的$ j_and_s数组取出?我试图把它作为第二个参数与$用户并列,但这不起作用,有什么想法?谢谢,-tim – 2012-02-07 05:16:26

0

尝试通过users阵列循环的j_and_s代替:

function sort_jerry_and_sue($users) 
{ 
    $j_and_s=array('[email protected]', '[email protected]'); 
    $not_js=array(); 
    foreach($users as $js){ 
      if(in_array($js['email'], $j_and_s)){ 
      } 
      else { 
       array_push($not_js, $users); 
      } 
    } 
    return $not_js; 
}