组合更新如果不插入多行

Question

我想要一个纯SQL查询来插入或更新多行。我开始工作之一，但是对于单排：

WITH UPDATED_ITEMS as (
    UPDATE table SET (columnC, columnD) = ($value3, $value4) WHERE id = $value5 returning * 
) 
INSERT INTO table (columnA, columnB, columnC, columnD) SELECT $value1, $value2, $value3, $value4 WHERE NOT EXISTS (SELECT * FROM updated_items) 

现在我已经改变了更新条件，但不知道如何与插入做到这一点：

WITH updated_items as (
    UPDATE table as m SET 
    columnC = c.columnC 
    columnD = c.columnD 
from (values ($value3, $value4, $value5), ($value8, $value9, $value10) 
) as c(columnC, columnD, id) 
where c.id::int4 = m.id returning * 
) 
INSERT INTO table (columnA, columnB, columnC, columnD) 
SELECT ($value1, $value2, $value3, $value4, $value5), ($value6, $value7, $value8, $value9, $value10) WHERE NOT EXISTS (SELECT * FROM updated_items) 

但嵌件不起作用。任何人都请帮忙？

Answer 1

我想你基本上需要not exists中的关联子句。您的更新引用了id列，所以我也添加了该列。所以我认为这是你想要的：

WITH updated_items as (
    UPDATE table as m 
    SET columnC = c.columnC, 
     columnD = c.columnD 
    FROM (VALUES ($value3, $value4, $value5), 
       ($value8, $value9, $value10) 
     ) as c(columnC, columnD, id) 
    WHERE c.id::int4 = m.id 
    RETURNING * 
    ) 
INSERT INTO table (columnA, columnB, columnC, columnD) 
    SELECT columnA, columnB, columnC, columnD 
    FROM (VALUES ($value1, $value2, $value3, $value4, $value5), 
       ($value6, $value7, $value8, $value9, $value10) 
     ) c(columnA, columnB, columnC, columnD, id) 
    WHERE NOT EXISTS (SELECT 1 FROM updated_items ui WHERE ui.id = c.id::int);