0
我不确定这是否可能,或者如果我采取了错误的方法,我尝试过搜索,但我不确定这些条款。变量字典内容
我想一个变量传递到控制器字典,因此而不是使用“PLAY”,在查找我可以做类似控制器从(“选项”,“玩”)
var ip = '192.168.1.5'
var Keys = {
HOME: '/keypress/Home',
REV: '/keypress/Rev',
FWD: '/keypress/Fwd',
PLAY: '/keypress/Play',
SELECT: '/keypress/Select',
LEFT: '/keypress/Left',
RIGHT: '/keypress/Right',
DOWN: '/keypress/Down',
UP: '/keypress/Up',
BACK: '/keypress/Back',
INSTANTREPLAY: '/keypress/InstantReplay',
INFO: '/keypress/Info',
BACKSPACE: '/keypress/Backspace',
SEARCH: '/keypress/Search',
ENTER: '/keypress/Enter',
A: '/keypress/Lit_a'
}
这样的:
var controller = {
PLAY:{
hostname: ip,
port: 8060,
path: Keys['PLAY'],
method: 'POST'
}
}
这样:
var controller = {
OPTION:{
hostname: ip,
port: 8060,
path: Keys[Key],
method: 'POST'
}
}
我试图避免以下
var controller = {
PLAY:{
hostname: ip,
port: 8060,
path: Keys['PLAY'],
method: 'POST'
}
FWD :{
hostname: ip,
port: 8060,
path: Keys['FWD'],
method: 'POST'
}
REV :{
hostname: ip,
port: 8060,
path: Keys['REV'],
method: 'POST'
}
...
}
究竟是什么问题? – epascarello 2013-02-08 17:16:38
我不希望为每个关键词都写一本字典,I.E.控制器将拥有所有的密钥(由密钥引用),我会为每个密钥复制主机名,端口,方法(很多额外的代码可能有更短的版本,IE也更容易阅读) – onaclov2000 2013-02-08 17:25:02
因此,制作一个方法'getOption(“PLAY”)'并返回带有新插入路径的对象。 – epascarello 2013-02-08 17:29:21