通过嵌套阵列控制器与查看laravel

Question

我是新来laravel，我试图从明确的问题 here

我控制器类似如下：

foreach($users as $user){ 
    $message[] = Model::where('id',$user->id)->get(); 
} 
$data['tests'] = $message; 
return View::make('user.index', $data); 

我的看法是：

@foreach($tests['message'] as $test) 
    id : {{$test->id}} 
@endforeach 

这给了我Undefined index: message

我已经在控制器中转储了$data。我的数组如下所示。在return语句之前，我将var_dump放置在控制器中。我的var_dump($data)显示：

array(1) { 
     ["tests"] => array(2) { 
      [0] => object(Illuminate\ Database\ Eloquent\ Collection) #515 (1) { ["items":protected]= > array(2) { 
       [0] => ["attributes": protected] => array(14) { 
        ["id"] => string(3) "12".... 

     } 
    } 
      [1] => object(Illuminate\ Database\ Eloquent\ Collection) #515 (1) { ["items":protected]= > array(2) { 
       [0] => ["attributes": protected] => array(14) { 
        ["id"] => string(3) "12".... 

     } 
    } 
    } 

我做错了什么。请帮助我

Answer 1

@foreach($tests as $test) 
//$test is an array returned by get query. 
    @foreach($test as $item) 
    id : {{$item->id}} 
    @endforeach 
@endforeach 

获取返回数组，如果你想返回一个元素，使用查找（）或第（）。

Answer 2

您的$tests['message']应该是$tests，因为您尚未在控制器中定义消息。

$message = array(); 
foreach($users as $user){ 
    $message[] = Model::where('id',$user->id)->get(); 
} 
$data['tests'] = $message; 
return View::make('user.index', $data); 

查看

@foreach($tests as $test) 
    id : {{$test->id}} 
@endforeach 

Answer 3

试试这个：

$users = App\User::all() 
foreach($users as $user){ 
    $message[] = Model::where('id',$user->id)->get(); 
} 
$data['tests'] = $message; 
return view('user.index', compact('data')); 

在视图/ user.index.blade.php

@foreach($data['tests'] as $test) 
    id : {{$test->id}} 
@endforeach