PHP访问JSON响应并打印

Question

我有下面的代码，只是想获取信息的内部下面和打印Status

"Email": { "Status": "in-queue" }

我真的新到PHP所以我对任何错误道歉，学习一门课。

{ 
    "APIResponse": { 
     "ResponseStatus": 1, 
     "Email": { 
      "EmailSid": "12893712893789", 
      "SentEmails": "my@email.com", 
      "Date": "2017-02-07 22:53:26", 
      "Subject": "700message", 
      "Status": "in-queue", 
      "TotalEmailSent": 1, 
      "TotalPrize": "0.0100", 
      "ApiVersion": "2" 
     } 
    } 
} 

我知道如何在JavaScript中做到这一点，但它似乎有点不同的PHP。

任何帮助表示赞赏感谢你们！ :)

Answer 1

下面是如何将JSON字符串转换成一个数组，并显示值的快速PHP例子：

$json = '{ "APIResponse": { "ResponseStatus": 1, "Email": { "EmailSid": "12893712893789", "SentEmails": "my@email.com", "Date": "2017-02-07 22:53:26", "Subject": "700message", "Status": "in-queue", "TotalEmailSent": 1, "TotalPrize": "0.0100", "ApiVersion": "2" } } }'; $array = json_decode($json, true); echo $array['APIResponse']['Email']['Status'];

注意每个子节点是如何成为关联数组中一个孩子。您还可以执行print_r($array);以查看本机PHP关联数组格式的整个结构。

Answer 2

<?php 
$json = '{ 
    "APIResponse": { 
     "ResponseStatus": 1, 
     "Email": { 
      "EmailSid": "12893712893789", 
      "SentEmails": "my@email.com", 
      "Date": "2017-02-07 22:53:26", 
      "Subject": "700message", 
      "Status": "in-queue", 
      "TotalEmailSent": 1, 
      "TotalPrize": "0.0100", 
      "ApiVersion": "2" 
     } 
    } 
}'; 


// if this API response's JSON is being stored as a string type local variable decode it first. 

$decoded_json = json_decode($json, true); 

//Optional but helps when programing var_dump($decoded_json); Use this to help visualize the nested array variables you need to access. 

// Use each array key to walk into and access the desired value 

echo $decoded_json['APIResponse']['Email']['Status']; 


?> 

*编辑考虑到误差的基础上，在您的评论的问题：

，同时仍然确保首先解码JSON作为上面提到的，下面应该让你访问这些值。

echo $decoded_json['APIResponse']['Errors']['Error'][0]['Code']; 

echo $decoded_json['APIResponse']['Errors']['Error'][0]['Message']; 

最后，更多的建议，如果你曾经难倒。尝试一次访问一个数组，从最外层开始，一直工作，总能帮助我！