错误：从bash脚本 “[参数太多”

Question

我有一个bash脚本：

#!/bin/bash 
pathToTestCasesFile=$1 

while IFS=';' read -r col1 col2 
do 

    if [[ $col1 == V[0-9]:* ]]; then 
     echo "decrypt" 
     if [[ "$(decrypt "$col1")" == "$col2" ]] ; then 
     echo "$col1 is equal to $col2" 
     else 
     echo "$col1 is not equal to $col2" 
     fi 
    else 
     echo "encrypt" 
     if [[ "$(encrypt $col1)" == "$col2" ]] ; then 
     echo "$col1 is equal to $col2" 
     else 
     echo "$col1 is not equal to $col2" 
     fi 
    fi 

done < $pathToTestCasesFile 

exit 0 

下面是测试文件：

alex;V1:IVjd9qcAbUrR954gyPDbKw== 
V1:IVjd9qcAbUrR954gyPDbKw==;alex 

输出看起来是这样的：

encrypt 
alex is not equal to V1:IVjd9qcAbUrR954gyPDbKw== 
decrypt 
V1:IVjd9qcAbUrR954gyPDbKw== is not equal to alex 
decrypt 

但输出应该说一切都是平等的。

我确信在解密后的命令等于另一个命令的值。我单独测试了它。

也许有比较的问题..

非常感谢您的帮助。

Answer 1

这应该工作：

#!/bin/bash 

while IFS=, read -r col1 col2 
do 
    echo "I got|$col1|$col2|" 

    if [[ "$col1" =~ V.:.* ]]; then 
     echo "decrypt" 
     if [[ "$(decrypt "$col1")" == "$col2" ]] ; then 
      echo "[$col1] is equal to [$col2]" 
     else 
      echo "[$col1] is not equal to [$col2]" 
     fi 
    else 
     echo "encrypt" 
     if [[ "$(encrypt "$col1")" == "$col2" ]] ; then 
      echo "[$col1] is equal to [$col2]" 
     else 
      echo "[$col1] is not equal to [$col2]" 
     fi 
    fi 
done < "$pathToTestCasesFile" 

为字段分隔符使用逗号, - 在你的代码。在示例数据中，您有;。如果您需要;将IFS=,更改为IFS=';'。