4
如果你能帮我弄清楚这个问题,我会很愉快的。通过程序集插件排除文件目录MAVEN
当我建立我的项目与.zip与maven < 程序集>插件。
<assembly xmlns="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/plugins/maven-assembly-plugin/assembly/1.1.2 http://maven.apache.org/xsd/assembly-1.1.2.xsd">
<id>dev</id>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${basedir}</directory>
<includes>
<include>/environments/dev/**/*.sh</include>
<include>/environments/dev/**/*.jil</include>
<include>/environments/dev/**/*.properties</include>
<include>/environments/dev/**/log4j2.xml</include>
</includes>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>/lib</outputDirectory>
<useProjectArtifact>true</useProjectArtifact>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
我收到以下文件结构:
build.zip----> environments__
|_DEV_
|_bin
|_properties
|_....
我目标是:
要Maven构建后得到以下文件结构:
build.zip---->
|_bin
|_properties
|_....
没有环境和DEV文件夹。
我读过maven文档(http://maven.apache.org/plugins/maven-assembly-plugin/advanced-descriptor-topics.html),我们可以排除一些文件目录。 这样:
<assembly>
....
<fileSets>
<fileSet>
<directory>${basedir}</directory>
<includes>
....
</includes>
<excludes>
<exclude>/environments/dev</exclude>
</excludes>
</fileSet>
</fileSets>
<dependencySets>
<dependencySet>
<outputDirectory>/lib</outputDirectory>
<useProjectArtifact>true</useProjectArtifact>
<scope>runtime</scope>
</dependencySet>
</dependencySets>
</assembly>
但它没有帮助。我仍然有以前的文件结构。