计数连续的行 - SQL Server 2008

我需要根据其他列中的值计算连续的行。计数连续的行 - SQL Server 2008

当谈到SQL时，我完全是新手 - 所以问一下如果有什么不清楚的地方。

我有SQL Server 2008，因此LEAD()和LAG()不起作用，与基于分区的窗口大小的OVER（）相同。

实施例的数据集：

SLOT     Blocked 
------------------------------- 
2015-02-09 07:00:00.000 0 
2015-02-09 07:15:00.000 0 
2015-02-09 07:30:00.000 0 
2015-02-09 07:45:00.000 1 
2015-02-09 08:00:00.000 1 
2015-02-09 08:15:00.000 1 
2015-02-09 08:30:00.000 0 
2015-02-09 08:45:00.000 0 
2015-02-09 09:00:00.000 0 
2015-02-09 09:15:00.000 0 
2015-02-09 09:30:00.000 1 
2015-02-09 09:45:00.000 1 
2015-02-09 10:00:00.000 1 
2015-02-09 10:15:00.000 1 
2015-02-09 10:30:00.000 0 
2015-02-09 10:45:00.000 0 
2015-02-09 11:00:00.000 0 
2015-02-09 11:15:00.000 0 
2015-02-09 11:30:00.000 0 
2015-02-09 11:45:00.000 0 
2015-02-09 12:00:00.000 0

的数据由SLOT排序。我想对分区where Blocked = 0上的行进行计数。

的结果集我想获得：

SLOT     Blocked  RowNum 
------------------------------------------- 
2015-02-09 07:00:00.000 0   1 
2015-02-09 07:15:00.000 0   2 
2015-02-09 07:30:00.000 0   3 
2015-02-09 07:45:00.000 1   0 
2015-02-09 08:00:00.000 1   0 
2015-02-09 08:15:00.000 1   0 
2015-02-09 08:30:00.000 0   1 
2015-02-09 08:45:00.000 0   2 
2015-02-09 09:00:00.000 0   3 
2015-02-09 09:15:00.000 0   4 
2015-02-09 09:30:00.000 1   0 
2015-02-09 09:45:00.000 1   0 
2015-02-09 10:00:00.000 1   0 
2015-02-09 10:15:00.000 1   0 
2015-02-09 10:30:00.000 0   1 
2015-02-09 10:45:00.000 0   2 
2015-02-09 11:00:00.000 0   3 
2015-02-09 11:15:00.000 0   4 
2015-02-09 11:30:00.000 0   5 
2015-02-09 11:45:00.000 0   6 
2015-02-09 12:00:00.000 0   7

提前感谢！

来源

2015-02-11 TotallyNewb

只是像这种情况下的情况下，继续进行条件遮光时= 0那么ROW_NUMBER（）OVER（PARTITION BY阻止ORDER BY封锁）ELSE 0 END – mohan111 2015-02-11 09:17:19

可能是我没有澄清足够 - 在“阻塞”列中找到1后，计数器必须重新启动，如预期结果示例中所示。也许我的terribad英语是问题。 – TotallyNewb 2015-02-11 09:42:07

数据中是否会有空白？ – 2015-02-11 09:47:01

对于SQL Server 2008，你可以解决它像这样

SELECT Slot 
     ,Blocked 
     ,CASE WHEN Blocked = 0 
       THEN ROW_NUMBER() OVER 
       (PARTITION BY rt.RunningTotal ORDER BY Slot) 
      ELSE 0 END RowNum 
FROM Table1 t 
CROSS APPLY (SELECT ISNULL(SUM(Blocked), 0) RunningTotal 
      FROM Table1 
      WHERE Slot < t.Slot 
      ) rt 
ORDER BY Slot

SQL小提琴（与你的表名称替换表1）：http://sqlfiddle.com/#!3/659a0/28

来源

2015-02-11 09:58:12

似乎你的排名在前3排中排名不合格。在你的小提琴中相同 – 2015-02-11 11:27:34

由于我的编辑建议被拒绝（???）我把它写成注释：你必须使用'SELECT ISNULL（SUM（Blocked），0）RunningTotal'来避免由第一行引起的自己的Partition缺少前面的行，因此RunningTotal为null。 – flo 2015-02-11 11:28:20

@flo，似乎有人拒绝了你所做的编辑建议。我现在编辑了，这解决了这个问题。 – 2015-02-11 11:39:20

由于您使用SQLSERVER 2008年，你需要使用row_number（）结束。计算有点复杂，但这个脚本会从2005年的sqlserver

;WITH CTE AS 
(
SELECT SLOT, row_number() over (order by SLOT)- 
row_number() over (partition by blocked order by SLOT) x, blocked 
FROM 
-- replace these lines with your real table 
--start test tabel 
(values 
(cast('2015-02-09 07:00:00.000' as datetime), 0) 
,('2015-02-09 07:15:00.000', 0),('2015-02-09 07:30:00.000', 0) 
,('2015-02-09 07:45:00.000', 1),('2015-02-09 08:00:00.000', 1) 
,('2015-02-09 08:15:00.000', 1),('2015-02-09 08:30:00.000', 0) 
,('2015-02-09 08:45:00.000', 0),('2015-02-09 09:00:00.000', 0) 
,('2015-02-09 09:15:00.000', 0),('2015-02-09 09:30:00.000', 1) 
,('2015-02-09 09:45:00.000', 1),('2015-02-09 10:00:00.000', 1) 
,('2015-02-09 10:15:00.000', 1),('2015-02-09 10:30:00.000', 0) 
,('2015-02-09 10:45:00.000', 0),('2015-02-09 11:00:00.000', 0) 
,('2015-02-09 11:15:00.000', 0),('2015-02-09 11:30:00.000', 0) 
,('2015-02-09 11:45:00.000', 0),('2015-02-09 12:00:00.000', 0)) x(SLOT,Blocked) 
-- end test tabel 
) 
SELECT 
    SLOT, 
    BLOCKED, 
    CASE WHEN blocked = 0 
    THEN 
     row_number() over (partition by x, blocked order by slot) 
    ELSE 0 end ROWNUMBER 
FROM cte 
ORDER BY slot

工作

来源

2015-02-11 10:00:15

有趣的问题.. !!

我能够使用这个代码如下实现：

CREATE TABLE #TestTable(SLOT DATETIME,BLOCKED INT); 

    INSERT #TestTable(SLOT,BLOCKED) 
    VALUES 
    ('2015-02-09 07:00:00.000' ,0), 
    ('2015-02-09 07:15:00.000' ,0), 
    ('2015-02-09 07:30:00.000' ,0), 
    ('2015-02-09 07:45:00.000' ,1), 
    ('2015-02-09 08:00:00.000' ,1), 
    ('2015-02-09 08:15:00.000' ,1), 
    ('2015-02-09 08:30:00.000' ,0), 
    ('2015-02-09 08:45:00.000' ,0), 
    ('2015-02-09 09:00:00.000' ,0), 
    ('2015-02-09 09:15:00.000' ,0), 
    ('2015-02-09 09:30:00.000' ,1), 
    ('2015-02-09 09:45:00.000' ,1), 
    ('2015-02-09 10:00:00.000' ,1), 
    ('2015-02-09 10:15:00.000' ,1), 
    ('2015-02-09 10:30:00.000' ,0), 
    ('2015-02-09 10:45:00.000' ,0), 
    ('2015-02-09 11:00:00.000' ,0), 
    ('2015-02-09 11:15:00.000' ,0), 
    ('2015-02-09 11:30:00.000' ,0), 
    ('2015-02-09 11:45:00.000' ,0), 
    ('2015-02-09 12:00:00.000' ,0) 


    SELECT * 
    FROM #TestTable 
    ORDER BY SLOT 


    ;WITH TestTableVw AS 
    (SELECT SLOT,BLOCKED,ROW_NUMBER() OVER(ORDER BY SLOT) RNum 
    FROM #TestTable 
    ) 
    SELECT T.SLOT,T.BLOCKED,CASE WHEN T.BLOCKED=0 THEN V1.RNum-ISNULL((SELECT MAX(V2.RNum) FROM TestTableVw V2 WHERE V2.RNum<V1.RNum AND V2.BLOCKED=1),0) ELSE 0 END 
    FROM #TestTable T 
    JOIN TestTableVw V1 ON T.SLOT=V1.SLOT 

    DROP TABLE #TestTable;

我希望这将有助于.. !!

谢谢，

Swapnil

来源

2015-02-11 10:55:49 Swapnil

@TotallyNewb：检查我提供的代码是否适合您。我已使用您提供的示例数据对此进行了测试。该代码生成问题中给出的预期输出。 – Swapnil 2015-02-11 12:03:53

计数连续的行 - SQL Server 2008

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