新的C和学习。我不断收到错误(C2664:'int readScores(int,int,int)':无法将参数1从'int *'转换为'int')。我不知道如何解决这个问题。我尝试过查找它,但不明白错误代码... 我该如何解决它? 任何指针和/或代码的提示将不胜感激。 感谢C错误不能将参数1从int *转换成int
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
// Functions
int readScores(int test1, int test2, int test3);
int determineGrade(int test1, int test2, int test3);
void print(int test1, int test2, int test3);
int main(void)
{
int test1;
int test2;
int test3;
readScores(&test1, &test2, &test3);
determineGrade(test1, test2, test3);
print(test1, test2, test3);
return 0;
}
void readScores(int *test1, int *test2, int *test3)
{
// Promts
printf("Hello, this program will determine");
printf("the grades of average test scores");
printf("to see if you passed or not this year.");
printf("Please enter in the three test...");
printf("Note: only enter scores that are (0-100)");
printf("Enter in test1\n");
scanf("%d", test1);
printf("Enter in test2\n");
scanf("%d", test2);
printf("Enter in test 3\n");
scanf("%d", test3);
return;
}
int determineGrade(int test1, int test2, int test3)
{
// Local declrations
int average;
// Math
average = 3/(test1 + test2 + test3);
return average;
}
void print(int test1, int test2, int test3)
{
int Grade;
Grade = determineGrade(test1, test2, test3);
if (Grade > 90)
{
printf("Great job you have an A %d int the class\n", Grade);
return;
}
else if (70 <Grade> 90, test3)
{
if (test3 < 90)
{
printf("Good job you got a A %d\n", Grade);
return;
}
else
{
printf("Easy Beezy you got a B %d for the class\n", Grade);
return;
}
return;
}
else if (50 <Grade> 70, test2, test3)
{
Grade = 2/(test2 + test3);
if (Grade > 70)
{
printf("You passed congrats you have a C %d for the class\n", Grade);
return;
}
else
{
printf("You have a D for the class %d\n", Grade);
return;
}
}
else if (Grade < 50)
{
printf("Yeah you might want to take this class again you have a F %d\n", Grade);
return;
}
return;
}
您的'readScores'声明与'readScores'的定义不符。参数类型不同。即使是返回类型也不同。这没有意义。你想通过做出不匹配的定义来做什么?你是代码的作者吗? – AnT