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我想要做的是在ASP.NET中创建一个简单的Web服务，并通过该Web服务从MSSQL服务器获取数据，并在我的Android应用程序中使用该数据。作为新手，我已经尝试了这个Helpful的链接。我已经使用了本教程所提出的相同架构。但在我的结果中解析结果（肥皂响应）时出现错误。如下所示。如何从android中的SOAP响应中获取数据？
<?xml version="1.0" encoding="utf-8"?> <soap:Envelope
> xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xmlns:xsd="http://www.w3.org/2001/XMLSchema">
> <soap:Body><findContactResponse xmlns="http://tempuri.org/" />
> </soap:Body> </soap:Envelope>
和GetPropertyCount（）方法返回0，另一方面，arrayindexoutofBound误差未来与索引为0
这是我的活动的代码。我在哪里实施了易于处理的异步任务。
public class MainActivity extends Activity {
/** Called when the activity is first created. */
private static final String SOAP_ACTION = "http://tempuri.org/findContact";
private static final String OPERATION_NAME = "findContact";// your webservice web method name
private static final String WSDL_TARGET_NAMESPACE = "http://tempuri.org/";
private static final String SOAP_ADDRESS = "http://10.0.2.2:58497/WebService/Service.asmx?wsdl";//"http://127.0.0.1:58497/WebService/Service.asmx";
protected static final String TAG = null;
TextView tvData1;
EditText edata;
Button button;
String studentNo;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tvData1 = (TextView)findViewById(R.id.textView1);
edata =(EditText)findViewById(R.id.editText1);
button=(Button)findViewById(R.id.button1);
button.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
studentNo=edata.getText().toString();
new Submit().execute(studentNo);
}
});
}
private class Submit extends AsyncTask<String, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected Void doInBackground(String... arg) {
// TODO Auto-generated method stub
SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
PropertyInfo propertyInfo = new PropertyInfo();
propertyInfo.type = PropertyInfo.STRING_CLASS;
propertyInfo.name = "eid";
Log.e("studentNo", studentNo);
request.addProperty(propertyInfo);
request.addProperty("eid", studentNo);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS);
httpTransport.debug = true;
try {
httpTransport.call(SOAP_ACTION, envelope);
Log.e("Dump", httpTransport.responseDump.toString());
SoapObject result=(SoapObject)envelope.bodyIn;
if(result!= null){
Log.e("response", result.toString());
//To get the data.
System.out.println("********Count : "+ result.getPropertyCount());
String resultData=result.getProperty(0).toString();
Log.e("Found", resultData);
}
else{
Log.e("Obj", result.toString());
}
}
catch (Exception exception) {
Log.e("Not Found", exception.toString());
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
/**
* A placeholder fragment containing a simple view.
*/
}
现在任何人都可以告诉我哪里出了问题吗？或者我怎样才能毫无例外地得到我的回应？调试后，我想出了这条线正在创建异常。
String resultData=result.getProperty(0).toString();
非常感谢您提供任何帮助。
http://programmingjungle.blogspot.com/2013/05/soap-client-on-android-using-jibx.html?m=1他们要么是疯狂的，要么在Android上找到了一种简单的肥皂方法 – Anthony 2014-11-25 09:33:28
It对我没有多大帮助。我正在寻找在数据解析的情况下发生araayindexOutofBound错误时应该怎么做？或者我需要做些什么来获得从Soap Response @Anthony解析的数据 – user3673503 2014-11-26 06:06:06