如何比较两个查询结果在同一个循环

Question

我有2 sql queries（每个一个学期）。这两个查询不具有相同的行数。每个包含3个参数：Article id_Customer Turnover。

这以下，其计算第一学期的请求：

select "LRU", "Client", round(sum("Montant_fac_eur")) 
from "foundry_sync"."data" 
where "Nature"='Repair'  

and extract(month from "Facturation") between 0+{{w_widget6.selectedValue}} and 5+{{w_widget6.selectedValue}} 
group by "LRU", "Client" 

查询的学期表示这样的：

{ 
    "LRU": [ 
    "ATSU", 
    "ATSU", 
    "ATSU", 
    "ATSU 
     . 
     . 
     . 
    ], 
"Client": [ 
    394, 
    594, 
    4001, 
    5725, 
    7057, 
    7090 
    . 
    . 
    . 
], 
"round": [ 
    20866, 
    16814, 
    27421, 
    0, 
    6593, 
    66965, 
    8401 
    . 
    . 
    . 
] 

这以下的结果的一个示例：

result 1      result2 

"[Article1,394,3914]"  "[Article1,394,3914]" 
"[Article1,594,16814]"  "[Article2,594,10088]" 
"[Article1,4001,26798]" "[Article1,4001,11107]" 
"[Article3,5725,0]"  "[Article3,5725,0]" 
"[Article5,7057,5700]"  "[Article5,7057,3916]" 
"[Article8,7090,56467]" "[Article4,7090,17558]" 
"[Article2,7236,8401]"  "[Article8,7236,8401]" 
"[Article11,7242,12766]" "[Article14,7242,4255]" 
"[Article2,7262,892]"  "[Article2,7262,892]" 
"[Article3,7302,17234]" "[Article3,7302,8928]" 

如您所见，客户可以在两个学期或一个学期仅在一个学期（第一个或第二个）的文章营业额。 我想首先比较每个学期每个customer每个Article的营业额。

var query1 = {{repair_semestre1}}; 
    var query2 = {{repair_semestre2}}; 
    var result1 = []; 
    var result2 = []; 


    for (var i = 0; i < query1.LRU.length; i++) { 
     result1.push(formatName(query1.LRU[i], query1.Client[i], query1.round[i])); 
    } 

    for (var i = 0; i < query2.LRU.length; i++) { 
     result2.push(formatName(query2.LRU[i], query2.Client[i], query2.round[i])); 
    } 

    return { 
     result1: result1, 
     result2: result2 
    }; 

    /* for (var i = 0; i < query1.LRU.length, i < query2.LRU.length; i++) { 
     if((query1.LRU[i] == query2.LRU[i]) && (query1.Client[i] == query2.Client[i])) { 
        if(query1.round[i] > query2.round[i]) { 
          return "ok"; 
        } 
        else { return "non"; 
        } 
     } 

    } */ 

    function formatName(lru, turnover, round) { 
     return "[" + lru + "," + turnover + "," + round + "]"; 
    } 

我做了一个循环的功能外，这些2个查询比较她的结果：

var query1 = {{repair_semestre1}}; 
var query2 = {{repair_semestre2}}; 
for (var i = 0; i < query1.LRU.length, i < query2.LRU.length; i++) { 
    if((query1.LRU[i] == query2.LRU[i]) && (query1.Client[i] == query2.Client[i])) { 
       if(query1.round[i] > query2.round[i]) { 
         return "ok"; 
       } 
       else { return "not ok"; 
       } 
    } 
} 

它仅返回not ok，不完成行的其余部分。可以请你解释一下为什么？ 如何在我的函数中添加这个循环来运行？

谢谢。

Answer 1

我建议首先将您的数据结构转换为将相关内容在一个对象中组合在一起的东西，而不是与索引编号链接。

例如，对于客户端594，谁是参与的两篇文章，这学期转旁白可以这样表示：

{ 
    "594": { 
    "Article1": [ 
     16814, 
     0 
    ], 
    "Article2": [ 
     0, 
     10088 
    ] 
    } 
} 

...其中内阵列始终有两个入口：每个的两个学期。该结构将允许轻松报告。

这里是以下这对于例如输出转换的代码：

// Sample data 
 
const query1 = { 
 
    LRU: ["Article1", "Article1", "Article1", "Article3", "Article5", 
 
      "Article8", "Article2", "Article11", "Article2", "Article3"], 
 
    Client: [394, 594, 4001, 5725, 7057, 7090, 7236, 7242, 7262, 7302], 
 
    round: [3914, 16814, 26798, 0, 5700, 56467, 8401, 12766, 892, 17234] 
 
}, query2 = { 
 
    LRU: ["Article1", "Article2", "Article1", "Article3", "Article5", 
 
      "Article4", "Article8", "Article14", "Article2", "Article3"], 
 
    Client: [394, 594, 4001, 5725, 7057, 7090, 7236, 7242, 7262, 7302], 
 
    round: [3914, 10088, 11107, 0, 3916, 17558, 8401, 4255, 892, 8928] 
 
}; 
 

 
// Convert to a more useful data structure, keyed by client and article 
 
const data = {}; 
 
[query1, query2].forEach(function (query, semester) { 
 
    query.Client.forEach(function(clientId, index) { 
 
     var client = data[clientId] = data[clientId] || {}; 
 
     var clientArt = client[query.LRU[index]] = client[query.LRU[index]] || [0, 0]; 
 
     clientArt[semester] = query.round[index]; 
 
    }); 
 
}); 
 

 
// Now report on that data 
 
for (const client in data) { 
 
    for (const article in data[client]) { 
 
     const turnovers = data[client][article]; 
 
     console.log('Client: ' + client + ', art.: ' + article 
 
        + ', semester t/o: ' + turnovers 
 
        + ' ' + (turnovers[0] === turnovers[1] ? 'equal' : 
 
          turnovers[0] < turnovers[1] ? 'increase' : 
 
                 'decrease')); 
 
    } 
 
}

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