在java中读取和解析KML

Question

是否有任何库可用于解析KML？

Answer 1

您将制作自己的图书馆，但您不会编写任何代码。

我建议看看http://code.google.com/apis/kml/documentation/kmlreference.html。从那里你可以得到XML Schema。获得架构后，您可以使用JAXB生成对象树，以轻松解析和编写KML。

This may also be a good resource，貌似别人已经做到了！

Answer 2

既然是XML，你可以用任何的解析器读取数据，但仍然有可用的LIB在http://code.google.com/p/libkml/它为Java绑定，但库在C++

Answer 3

这个库看起来很有希望，以及：

http://code.google.com/p/javaapiforkml/

该库提供了至今的支持。

Answer 4

这里是我的JSOUP实现希望它有助于

public ArrayList<ArrayList<LatLng>> getCoordinateArrays() { 
    ArrayList<ArrayList<LatLng>> allTracks = new ArrayList<ArrayList<LatLng>>(); 

    try { 
     StringBuilder buf = new StringBuilder(); 
     InputStream json = MyApplication.getInstance().getAssets().open("track.kml"); 
     BufferedReader in = new BufferedReader(new InputStreamReader(json)); 
     String str; 
         String buffer; 
     while ((str = in.readLine()) != null) { 
      buf.append(str); 
     } 

     in.close(); 
     String html = buf.toString(); 
     Document doc = Jsoup.parse(html, "", Parser.xmlParser()); 
     ArrayList<String> tracksString = new ArrayList<String>(); 
     for (Element e : doc.select("coordinates")) { 
      tracksString.add(e.toString().replace("<coordinates>", "").replace("</coordinates>", "")); 
     } 

     for (int i = 0; i < tracksString.size(); i++) { 
      ArrayList<LatLng> oneTrack = new ArrayList<LatLng>(); 
      ArrayList<String> oneTrackString = new ArrayList<String>(Arrays.asList(tracksString.get(i).split("\\s+"))); 
      for (int k = 1; k < oneTrackString.size(); k++) { 
       LatLng latLng = new LatLng(Double.parseDouble(oneTrackString.get(k).split(",")[0]), 
         Double.parseDouble(oneTrackString.get(k).split(",")[1])); 
       oneTrack.add(latLng); 
      } 
      allTracks.add(oneTrack); 
     }} 

    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    return allTracks; 
} 

Answer 5

osmbonuspack作品真的很好的处理KML数据情况。

Answer 6

，如果你使用Android工作室:)

dependencies { 
    compile 'org.jsoup:jsoup:1.8.1' 
} 


     // find a way to read the file and store it in a string 

     String inputFileContents = ""; 
     String xmlContent = inputFileContents; 
     Document doc = Jsoup.parse(xml, "", Parser.xmlParser()); 

     for(Element e : doc.select("LineString").select("coordinates")) { 
      // the contents 
      System.out.println(e.text()); 
     } 

你可以有多个选择（）方法调用。 我简化了代码：

Element e = doc.select("LineString").select("coordinates").first(); 

Answer 7

这是其他选项，KML文件是一个正常的文件，谁包含结构的XML文件。 这是另一个例子，搜索一个特定的地标文件中的多个地标

private static void readKML(InputStream fileKML, String nameCoordinates) { 
    String column = null; 
    Boolean folder = Boolean.TRUE; 
    Boolean placemark = Boolean.FALSE; 
    Boolean placeCorrect = Boolean.FALSE; 
    BufferedReader br = new BufferedReader(new InputStreamReader(fileKML)); 
    try { 
     while ((column = br.readLine()) != null) { 
      if (folder) { 
       int ifolder = column.indexOf("<Folder>"); 
       if (ifolder != -1) { 
        folder = Boolean.FALSE; 
        placemark = Boolean.TRUE; 
        continue; 
       } 
      } 
      if (placemark) { 
       String tmpLine = nameCoordinates; 
       tmpLine = tmpLine.replaceAll("\t", ""); 
       tmpLine = tmpLine.replaceAll(" ", ""); 
       String tmpColumn = column; 
       tmpColumn = tmpColumn.replaceAll("\t", ""); 
       tmpColumn = tmpColumn.replaceAll(" ", ""); 
       int name = tmpColumn.indexOf(tmpLine); 
       if (name != -1) { 
        placemark = Boolean.FALSE; 
        placeCorrect = Boolean.TRUE; 
        continue; 
       } 
      } 
      if (placeCorrect) { 
       int coordin = column.indexOf("<coordinates>"); 
       if (coordin != -1) { 
        String tmpCoordin = column; 
        tmpCoordin = tmpCoordin.replaceAll(" ", ""); 
        tmpCoordin = tmpCoordin.replaceAll("\t", ""); 
        tmpCoordin = tmpCoordin.replaceAll("<coordinates>", ""); 
        tmpCoordin = tmpCoordin 
          .replaceAll("</coordinates>", ""); 
        String[] coo = tmpCoordin.split(","); 
        System.out.println("LONG: "+coo[0]); 
        System.out.println("LATI: "+coo[1]) 
        break; 
       } 
      } 

     } 
     br.close(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
    return cresp; 
}