添加子查询

我有以下查询，并且我正在尝试生成四列，即买方，源，总数和返回的潜在客户。添加子查询

问题在于包含一个包含导联总数的列。返回的是我的数据库中的一列，其值为0或1.所以返回的是1的所有东西，但对于买过的导致，我需要的所有东西都是0.当我运行以下查询时，所有购买的导致最终成为0.我如何修复子查询以获得期望的结果。

SELECT 
    ba.buyer, 
    l.source, 
    (SELECT COUNT(*) FROM lead_status WHERE lead_id = l.id AND returned != 1) AS 'Bought Leads', 
    SUM(l.returned) AS 'Returned_Leads' 
FROM lead_status AS ls 
    LEFT JOIN leads AS l ON ls.lead_id = l.id 
    LEFT JOIN buyer_account AS ba ON ba.lead_buyer_id = ls.lead_buyer_id 
WHERE l.origin = 'PING_POST' 
    AND ls.discriminator IN('AUTO_POST','HOME_POST','HEALTH_POST','LIFE_POST') 
    AND DATE(ls.create_date) BETWEEN '2012-02-01' AND '2012-02-31' 
    AND l.sold = 1 AND ls.winner = 1 AND l.test = 0 AND l.returned = 1 
GROUP BY ls.buyer, l.source;

来源

2012-03-02 ATMathew

只是更换子查询：

SUM(1-l.returned)

只要它有点领域，否则你应该让两个和一个CASE操作statment即总和（情况时返回0，1否则为0结束）。

来源

2012-03-02 21:53:15

创意，我喜欢它比我多。效率也更高。 – JKomusin 2012-03-02 21:58:13

如果不是位域，则采用减法的abs（）得出0和1的值 – Sparky 2012-03-02 22:53:29

尝试

SUM(abs(l.returned-1))

如果返回为0，它会返回-1
仿佛回到了1，返回0

服用ABS（）价值给你+1所以你的SUM（）应该工作

来源

2012-03-02 21:50:38 Sparky

我想你可以做到这一点作为替代，如果它是一个二进制的1或0：

SELECT 
    ba.buyer, 
    l.source, 
    COUNT(l.returned) - SUM(l.returned) AS 'Bought Leads', 
    SUM(l.returned) AS 'Returned_Leads' 
FROM lead_status AS ls 
    LEFT JOIN leads AS l ON ls.lead_id = l.id 
    LEFT JOIN buyer_account AS ba ON ba.lead_buyer_id = ls.lead_buyer_id 
WHERE l.origin = 'PING_POST' 
    AND ls.discriminator IN('AUTO_POST','HOME_POST','HEALTH_POST','LIFE_POST') 
    AND DATE(ls.create_date) BETWEEN '2012-02-01' AND '2012-02-31' 
    AND l.sold = 1 AND ls.winner = 1 AND l.test = 0 AND l.returned = 1 
GROUP BY ls.buyer, l.source;

来源

2012-03-02 21:54:50 JKomusin

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