2017-06-14 23 views
3

我使用Spring 4和休眠5是否有可能让我的自定义验证注释在持续时被忽略?

我有用户类与密码字段与自定义验证。

我需要验证它,而表单绑定为8个字符长,包括小写字母,大写字母和数字。

当用户输入密码时它是有效的,但是当我编码时它是无效的。

那么有没有办法让我的自定义验证注释被忽略持续?

我知道我可以为未加密的密码创建不同的字段,或者使数据传输对象验证它,然后将其数据分发给用户。 但我对注释参数化的可能性感兴趣。

@Entity 
@Table(name = "user") 
public class User { 
//other fields 

@NotNull 
@NotEmpty 
@ValidPassword 
@Column(name = "password", nullable = false, length = 60) 
private String password; 
//getters and setters 
} 

我的验证

@Target({ TYPE, FIELD, ANNOTATION_TYPE }) 
@Retention(RUNTIME) 
@Constraint(validatedBy = PasswordValidator.class) 
@Documented 
public @interface ValidPassword { 
String message() default "Password is too short! Must be 8 digits and include lowercase, uppercase letters and numbers."; 

Class<?>[] groups() default {}; 

Class<? extends Payload>[] payload() default {}; 
} 

public class PasswordValidator implements ConstraintValidator<ValidPassword, String> { 

private Pattern pattern; 
private Matcher matcher; 
private static final String PATTERN = "((?=.*\\d)(?=.*[a-z])(?=.*[A-Z]).{8,})"; 

@Override 
public void initialize(ValidPassword constraintAnnotation) { 
} 

@Override 
public boolean isValid(String password, ConstraintValidatorContext context) { 
    return (validate(password)); 
} 

private boolean validate(String password) { 
    pattern = Pattern.compile(PATTERN); 
    matcher = pattern.matcher(password); 
    return matcher.matches(); 
} 
} 

控制方法

@RequestMapping(value = "/registeruser", method = RequestMethod.POST) 
public String registerUser(@ModelAttribute("user") @Valid User user, BindingResult result, Model model) { 
    if (result.hasErrors()) { 
     model.addAttribute("errorSummary", result.getFieldErrors().stream() 
       .map(e -> e.getField() + " error - " + e.getDefaultMessage() + " ").collect(Collectors.toList())); 
     model.addAttribute("user", user); 

    } else { 
     User registered = null; 
     registered = createUserAccount(user, result); 

     if (registered == null) { 
      model.addAttribute("errorSummary", "User with this email already registered!"); 
      model.addAttribute("user", user); 
      return "registration"; 
     } 
     model.addAttribute("flashMessage", "User registered successfully!"); 
    } 

    return "registration"; 
} 

UserService实现方法(在这里我编码我的密码)

@Transactional 
@Override 
public User registerNewUserAccount(User user) throws EmailExistsException { 

    if (emailExist(user.getEmail())) { 
     throw new EmailExistsException("There is an account with that email address:" + user.getEmail()); 
    } 

    if (user.getPassword() == null) { 
     user.setPassword(new BigInteger(130, new SecureRandom()).toString(32)); 
     System.out.println("+++++++++++++++" + user.getPassword()); 
    } 
    user.setPassword(passwordEncoder.encode(user.getPassword())); 
    user.setUserRole(new HashSet<UserRole>(1)); 
    user.getUserRole().add(new UserRole(user, Constants.RoleType.USER.name())); 
    save(user); 
    return user; 
} 
+0

Waht确实“无效,当我编码”,确切地说,在代码中的哪个位置得到该错误? – zaph

+0

我在一个月前遇到过这样的情况,当时我只想在持久化上运行验证。请参阅:https://stackoverflow.com/questions/43964065/hibernate-validations-on-save-insert-only/43984952#43984952。您必须将验证设置为在“javax.persistence.validation.group.pre-update”(可能是“javax.persistence.validation.group.pre-remove”)期间执行。看到完整的文档在这里:https://docs.jboss.org/hibernate/orm/3.6/reference/en-US/html/additionalmodules.html –

+0

@ zaph当用户输入正确的密码是有8位数等等,当我使用'passwordEncoder.encode(user。getPassword())'它现在变得更长了(例如:$ 2a $ 10 $ 3/ufbdU3qMnn7e3IQ7hkjubrdRJrD7kKieAqflKEDvZ8b7DY8eUcu),所以验证失败 –

回答

1

默认情况下,所有约束都会进行验证。或者你也可以指定Grouping Constraints

您可以通过创建一个接口创建组:

interface FormValidationGroup{} 

和注释password场这样的:

@ValidPassword(groups = FormValidationGroup.class) 
private String password; 

文档为Custom Constraints annotations,其中groups参数被提及。

除非您指定验证组,否则Hibernate验证程序现在应忽略password字段。为了指定一个用于验证Spring MVC处理程序方法参数的组,请使用Validated注释而不是Valid。例如:

String registerUser(@ModelAttribute @Validated(FormValidationGroup.class) User user, 
     BindingResult result, Model model) { 
    if (result.hasErrors()) { 
+0

这很有用。但是,如何让我的自定义组在form绑定上得到验证,所以我可以使用BindingResult'hasErrors()'方法? –

+1

我更新了我的答案,以展示如何使用Spring MVC和'BindingResult'的自定义组 –

相关问题