带分支的代码

Question

def which_prize(): 
    return "Congratulations! You have won a [prize name]!" 
    if Points ==0 or Points ==50: 
     print("Congratulations! You have won a [wooden rabbit]!") 
    elif Points ==0 or Points ==150: 
     print("Congratulations! You have won a [no prize]!") 
    elif Points==151 or Points ==180: 
     print("Congratulations! You have won a [wafer-thin mint]!") 
    elif Points ==181 or Points ==200: 
     print("Congratulations! You have won a [penguin]!") 

    else: 
     print("Oh dear, no prize this time.") 

输入到which_prize()将是点数（整数）。函数which_prize()应返回文本“恭喜！您赢得了[奖品名称]！”如果他们赢得了奖品并且文字“哦，亲爱的，这次没有奖品”，那么将包括奖品名称。如果没有奖品。像往常一样，测试你的功能来检查它是否正确执行。

IndentationError: unindent does not match any outer indentation level.

Answer 1

你也许混合选项卡和空间。 尝试取消缩进代码并仅使用制表符（或空格）缩进它

PS：您如何期待您的代码被运行：函数在return语句后结束。

尝试：

def which_prize(): 
    if Points and Points <=50: 
    return("Congratulations! You have won a [wooden rabbit]!") 
    elif Points <= 150: 
    return "Congratulations! You have won a [no prize]!") 
    elif Points <= 180: 
    return "Congratulations! You have won a [wafer-thin mint]!") 
    elif Points > 180: 
    return "Congratulations! You have won a [penguin]!") 
    else: 
     return "Oh dear, no prize this time."