根据spring-boot项目构建可部署的WAR

Question

我想从Spring启动项目创建一个WAR文件，它允许用户运行java -jar filename的文件并使用tomcat部署此文件。

现在，我有这样的配置：

的pom.xml

<?xml version="1.0" encoding="UTF-8"?> 
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> 
    <modelVersion>4.0.0</modelVersion> 

    <groupId>org.springframework</groupId> 
    <artifactId>springapp</artifactId> 
    <version>1.0.0</version> 
    <packaging>war</packaging> 

    <parent> 
     <groupId>org.springframework.boot</groupId> 
     <artifactId>spring-boot-starter-parent</artifactId> 
     <version>1.2.6.RELEASE</version> 
    </parent> 

    <dependencies> 
     <dependency> 
      <groupId>org.springframework.boot</groupId> 
      <artifactId>spring-boot-starter-web</artifactId> 
     </dependency> 
     <dependency> 
      <groupId>org.springframework.boot</groupId> 
      <artifactId>spring-boot-starter-tomcat</artifactId> 
      <scope>provided</scope> 
     </dependency> 
    </dependencies> 

    <properties> 
     <java.version>1.7</java.version> 
    </properties> 


    <build> 
     <plugins> 
      <plugin> 
       <groupId>org.springframework.boot</groupId> 
       <artifactId>spring-boot-maven-plugin</artifactId> 
      </plugin> 
     </plugins> 
    </build> 

</project> 

Application.java

package org.hello; 

import org.springframework.boot.SpringApplication; 
import org.springframework.boot.autoconfigure.SpringBootApplication; 
import org.springframework.boot.context.web.SpringBootServletInitializer; 
import org.springframework.boot.builder.SpringApplicationBuilder; 

@SpringBootApplication 
public class Application extends SpringBootServletInitializer { 

    public static void main(String[] args) { 
     SpringApplication.run(Application.class, args); 
    } 

    @Override 
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) { 
     return application.sources(Application.class); 
    } 

} 

HelloController.java

package org.hello; 

import org.springframework.web.bind.annotation.RestController; 
import org.springframework.web.bind.annotation.RequestMapping; 

@RestController 
public class HelloController { 

    @RequestMapping("/") 
    public String index() { 
     return "Greetings from Spring Boot!"; 
    } 

} 

使用此配置，我可以在命令行中使用java -jar filename运行应用程序，但是当我在tomcat中部署war时，当访问/ page时会出现404错误页面。 （部署应用程序时不显示错误）。

我在这里失踪了什么？

Answer 1

默认情况下，Spring Boot要求您的容器支持Servlet 3.0或更高版本。 Tomcat 6只支持Servlet 2.5。最简单的选择是升级到Tomcat 7或8.

如果您无法升级到Tomcat 7或8，那么仍然可以让您的应用程序运行。但是，它需要更多的努力。作为described in the documentation，你需要添加org.springframework.boot:spring-boot-legacy的依赖，并添加web.xml具有以下内容：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> 

    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>demo.Application</param-value> 
    </context-param> 

    <listener> 
     <listener-class>org.springframework.boot.legacy.context.web.SpringBootContextLoaderListener</listener-class> 
    </listener> 

    <filter> 
     <filter-name>metricFilter</filter-name> 
     <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> 
    </filter> 

    <filter-mapping> 
     <filter-name>metricFilter</filter-name> 
     <url-pattern>/*</url-pattern> 
    </filter-mapping> 

    <servlet> 
     <servlet-name>appServlet</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <init-param> 
      <param-name>contextAttribute</param-name> 
      <param-value>org.springframework.web.context.WebApplicationContext.ROOT</param-value> 
     </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 

    <servlet-mapping> 
     <servlet-name>appServlet</servlet-name> 
     <url-pattern>/</url-pattern> 
    </servlet-mapping> 

</web-app>