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我困在以下问题上; 我有一个矩形(50x40像素可以说,位置:x1,y1)和一个圆形(半径30,positin x2,y2)。现在我想提请他们Java - 在具有静态尺寸的两个对象之间绘制箭头
void drawArrow(Graphics g1, int x1, int y1, int x2, int y2,) {
//x1 and y1 are coordinates of circle or rectangle
//x2 and y2 are coordinates of circle or rectangle, to this point is directed the arrow
Graphics2D g = (Graphics2D) g1.create();
double dx=x2-x1;
double dy=y2-y1;
double angle = Math.atan2(dy, dx);
int len = (int) Math.sqrt(dx*dx + dy*dy);
AffineTransform at = AffineTransform.getTranslateInstance(x1, y1);
at.concatenate(AffineTransform.getRotateInstance(angle));
g.transform(at);
g.drawLine(0,0,len,0);
g.fillPolygon(new int[] {len, len-ARR_SIZE, len-ARR_SIZE, len},
new int[] {0, -ARR_SIZE, ARR_SIZE, 0}, 4);
}
本准则之间的箭头显然只连接矩形和圆形的特定点(在这张照片我在中间http://imageshack.us/photo/my-images/341/arrk.jpg/连接点)。你有什么想法如何实现这样的stg? (http://imageshack.us/photo/my-images/833/arr2u.jpg/)...我的想法是缩短长度并计算新坐标,但我有点挣扎。
//我调用这个函数是这样的:
drawArrow(g,temp.x+radius/2,temp.y+radius/2,temp2.x+width/2,temp2.y+height/2);