assertTesting函数成功或失败测试

Question

我想在这里创建一个assertTesting函数，它比较实际值和期望值与严格相等（不是类型转换）。

此处作为一例是一个成功的案例：

function multiplyByTwo(n) { 
    return n * 2; 
} 
var output = multiplyByTwo(2); // returns 4 
assertTesting(output, 4, 'it doubles 2 to 4'); 
// console output: 
// passed 

这里是一个失败的一个：

function multiplyByTwo(n) { 
    return (n * 2) + 1; // an incorrect implementation 
} 
var output = multiplyByTwo(2); // returns 5 
assertTesting(output, 4, 'it doubles 2 to 4'); 
// console output: 
// FAILED [it doubles 2 to 4] Expected "4", but got "5" 

这里是到目前为止我的代码：

var output; 

function multiplyByTwo(n) { 
    output = n * 2; 
    return output; 
} 

function assertTesting (actual, expected, testName) { 
    if(actual === ouput && expected === testName){ 
    return "SUCCESS" + [testname] + "Expected" + expected + "," "but got" + actual; 
    } 
} 

任何想法我如何能得到我需要的确切输出？请帮忙。

Answer 1

应该是这样的，我想：

function assertEqual(actual, expected, testName) { 
    if(actual !== expected){ 
    console.error("FAIL [" + testname + "] Expected \"" + expected + ", \" but got \"" + actual + "\""); 
    } else { 
    console.info("SUCCESS [" + testname + "]"); 
    } 
}