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我有一个32位的wav阵列,我想将其转换为8位转换32位的wav阵列x比特
所以,我试图借此功能,其将32至16
void _waveIn_DataAvailable(object sender, WaveInEventArgs e)
{
byte[] newArray16Bit = new byte[e.BytesRecorded/2];
short two;
float value;
for (int i = 0, j = 0; i < e.BytesRecorded; i += 4, j += 2)
{
value = (BitConverter.ToSingle(e.Buffer, i));
two = (short)(value * short.MaxValue);
newArray16Bit[j] = (byte)(two & 0xFF);
newArray16Bit[j + 1] = (byte)((two >> 8) & 0xFF);
}
}
并将其修改为拍摄X位为目的地
private byte[] Convert32BitRateToNewBitRate(byte[] bytes, int newBitRate)
{
var sourceBitRate = 32;
byte[] newArray = new byte[bytes.Length/(sourceBitRate/newBitRate)];
for (int i = 0, j = 0; i < bytes.Length; i += (sourceBitRate/8), j += (newBitRate/8))
{
var value = (BitConverter.ToSingle(bytes, i));
var two = (short)(value * short.MaxValue);
newArray[j] = (byte)(two & 0xFF);
newArray[j + 1] = (byte)((two >> 8) & 0xFF);
}
return newArray;
}
我的问题是,我不知道如何将代码转换中的“for”循环,我试图调试它,但我不能完全弄清楚怎么运行的。
我在这里看到:simple wav 16-bit/8-bit converter source code?,它们除以256的值从16到8,我试图用256除以32至16获得,但它没有工作
for (int i = 0, j = 0; i < bytes.Length; i += sourceBitRateBytes, j += newBitRateBytes)
{
var value = BitConverter.ToInt32(bytes, i);
value /= (int)Math.Pow(256, sourceBitRate/newBitRate/2.0);
var valueBytes = BitConverter.GetBytes(value);
for (int k = 0; k < newBitRateBytes; k++)
{
newArray[k + j] = valueBytes[k];
}
我可以在背景中听到很多静态的声音,我想我们需要了解他们使用的代码。 – user779444
我看到http://stackoverflow.com/questions/6494505/simple-wav-16-bit-8-bit-converter-source-code他们转换除以256 – user779444
一个问题可能是,它是从-128到你可以尝试127和'sbyte'而不是byte.MaxValue吗? –