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例如鉴于这种urlscrapy css选择器链如何表示当前节点?
我想获得卖家的DIV
使用XPath,首先我用CSS来得到一个特定的卖家行,然后我用“./”来指代当前节点,那么我可以得到(5) div放在我的目标div(行)之后。 B的
b = response.css('div#olpOfferList div.a-row.a-spacing-mini.olpOffer')[1].xpath('./div')
结果:
<Selector xpath='./div' data=u'<div class="a-column a-span2 olpPriceCol'>
<Selector xpath='./div' data=u'<div class="a-column a-span3 olpConditio'>
<Selector xpath='./div' data=u'<div class="a-column a-span3 olpDelivery'>
<Selector xpath='./div' data=u'<div class="a-column a-span2 olpSellerCo'>
<Selector xpath='./div' data=u'<div class="a-column a-span2 olpBuyColum'>
但随着CSS,我也不怎么选择当前节点的
a = response.css('div#olpOfferList div.a-row.a-spacing-mini.olpOffer')[1].css('div > div')
结果后指当前节点:
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span2 olpPriceCol'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span3 olpConditio'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-section a-spacing-small">\n'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span3 olpDelivery'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span2 olpSellerCo'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span2 olpBuyColum'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-button-stack">\n '>
我试过这个但得到一个错误r:
a = response.css('div#olpOfferList div.a-row.a-spacing-mini.olpOffer')[1].css('> div')
如何用css引用当前节点? :D感谢您的帮助!
感谢您澄清我的难题! – Tianqing