我需要从表

我使用此查询得到以下结果得到日期智者总： -我需要从表

$date = $row['date']; 

$t_fee = mysql_query("SELECT sum(labs.test_fee), sum(labs.discount), sum(labs.received) from labs join patients on labs.p_id = patients.p_id where date = '$date'"); 


while($row = mysql_fetch_array($t_fee)) { 


    $fee_sum = $row[0]; 
    $discount_sum = $row[1]; 
    $received = $row[2]; 
    $after_discount = $fee_sum - $discount_sum; 
    $balance = $after_discount - $received;

----------------------------- 
Date  | Total Revenue | 
----------------------------- 
2017-05-23 | 1,000  | 
2017-05-19 | 4,190  | 
2017-05-19 | 4,190  | 
2017-05-19 | 4,190  | 
2017-05-18 | 1,350  | 
2017-05-08 | 690   | 
2017-05-02 | 2,280  | 
----------------------------- 
Grand Total | 9,510  | 
-----------------------------

我想要得到这样的结果： -

----------------------------- 
Date  | Total Revenue | 
----------------------------- 
2017-05-23 | 1,000  | 
2017-05-19 | 4,190  | 
2017-05-18 | 1,350  | 
2017-05-08 | 690   | 
2017-05-02 | 2,280  | 
----------------------------- 
Grand Total | 9,510  | 
-----------------------------

来源

2017-05-25 Imran

'... where date ='$ date'GROUP BY date“' – Mohammad

or select distinct（date）.... where date ='$ date' –

您必须使用mysqli扩展而不是mysql，因为这样如果用户输入'$ date'，你应该使用PDO或准备好的语句来避免sql注入。 – Mohammad

where date = '$date' 
group by date;

您需要按日期进行分组，以便在查询中附加group by date;。

来源

2017-05-25 07:52:04

我试着用group by date;但它不工作。 – Imran

回答

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