关于C点，无法理解的输出

Question

#include<stdio.h> 

typedef unsigned char * char_point; 

char_point int_cp(int i) 
{ 
    printf("i: %d\n", i); 
    printf("&i: %p\n", &i); 
    printf("(c_p)&i: %p\n", (char_point) &i); 
    char_point cp = (char_point) &i; 
    return cp; 
} 


char_point float_cp(float f) 
{ 
    printf("f: %f\n", f); 
    printf("&f: %p\n", &f); 
    printf("(c_p)&f: %p\n", (char_point) &f); 
    char_point cp = (char_point) &f; 
    return cp; 
} 

void endian(char_point cp, int size) 
{ 
    for (int i=0; i<size; i++) 
    { 
     printf("0x%x\n", cp[i]); 
    } 

} 

int main() 
{ 
    int i = 0x21893678; 
    float f = 913.45678f; 

    endian(int_cp(i), sizeof(i)); 
    // endian((char_point) &i, sizeof(i));  except like this 
    printf("== == == === = ==== === = == = == \n"); 
    // endian((char_point) &f, sizeof(f)); 
    endian(float_cp(f), sizeof(f)); 
} 

结果：

i: 562640504 
&i: 0x7ffdddb42fac 
(c_p)&i: 0x7ffdddb42fac 
0xfd 
0x7f 
0x0 
0x0 
== == == === = ==== === = == = == 
f: 913.456787 
&f: 0x7ffdddb42fac 
(c_p)&f: 0x7ffdddb42fac 
0xfd 
0x7f 
0x0 
0x0 

例外：

Answer 1

此换货政... RNS一个指向本地I：

char_point cp = (char_point) &i; 

和一个指向本地F：

char_point cp = (char_point) &f; 

一次函数返回时，他们得到释放的功能