我在模型中遇到了HABTM关系的问题。我在这个网站上搜索了很多例子和参考资料,并且在几个星期内没有成功。该类文章文章HABTM标签官方文档效果很好,但外推到我的模型失败。发现的所有信息不包含复合主键的实例或引用(我怀疑是因为复合主键的关系将无法正常工作,我不能老是改变这种模式)CakePHP:HABTM和递归属性获取所有相关数据
我的目标是让关系:
Customer HABTM Products.
所以,用
$客户= $这个 - >客户 - >找到( '所有');
获取客户对象中与客户相关的所有产品的数组。
目前我不能得到这个工作:$客户没有spected 产品阵列。
我感谢任何帮助或引用来帮助我解决这个问题。
这是我的分贝:
CREATE TABLE `customers` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`lang` varchar(2) NOT NULL,
`name` varchar(145) NOT NULL,
`logo` varchar(145) NOT NULL,
`description` text,
PRIMARY KEY (`id`,`lang`)
) ENGINE=InnoDB AUTO_INCREMENT=11 DEFAULT CHARSET=utf8
CREATE TABLE `products` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`lang` varchar(2) NOT NULL,
`category_id` int(11) NOT NULL,
`service_id` int(11) NOT NULL,
`description` text,
`picture` varchar(145) NOT NULL,
PRIMARY KEY (`id`,`category_id`,`service_id`,`lang`),
KEY `fk_products_services1` (`service_id`,`lang`),
KEY `fk_products_categories1` (`category_id`,`lang`),
CONSTRAINT `fk_products_categories1` FOREIGN KEY (`category_id`, `lang`) REFERENCES `categories` (`id`, `lang`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `fk_products_services1` FOREIGN KEY (`service_id`, `lang`) REFERENCES `services` (`id`, `lang`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=29 DEFAULT CHARSET=utf8
CREATE TABLE `customer_products` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`customer_id` int(11) NOT NULL,
`product_id` int(11) NOT NULL,
PRIMARY KEY (`id`,`customer_id`,`product_id`),
KEY `fk_customer_products_products1` (`product_id`),
KEY `fk_customer_products_customers` (`customer_id`),
CONSTRAINT `fk_customer_products_customers` FOREIGN KEY (`customer_id`) REFERENCES `customers` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `fk_customer_products_products1` FOREIGN KEY (`product_id`) REFERENCES `products` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
这是我的客户模型:
<?php
App::uses('AppModel', 'Model');
/**
* Customer Model
*
* @property CustomerProduct $CustomerProduct
* @property Product $AllProducts
*/
class Customer extends AppModel {
/**
* Display field
*
* @var string
*/
public $displayField = 'name';
//The Associations below have been created with all possible keys, those that are not needed can be removed
/**
* hasAndBelongsToMany associations
*
* @var array
*/
public $hasAndBelongsToMany = array(
'Products' => array(
'className' => 'Product',
'joinTable' => 'customer_products',
'foreignKey' => 'customer_id',
'associationForeignKey' => 'product_id',
'unique' => true,
'conditions' => '',
'fields' => '',
'order' => '',
'limit' => '',
'offset' => '',
'finderQuery' => '',
'deleteQuery' => '',
'insertQuery' => ''
)
);
}
这是我的索引客户控制器的方法:
public function index() {
$this->layout = 'header_chico';
$this->Customer->recursive = 0;
$customers = $this->Customer->find('all');
$this->set('customers', $customers);
}
谢谢@Chuck。我在我的测试环境中尝试过,但没有成功。我还没有产品阵列。无论如何,我无法在生产服务器中更改数据库模式(这就是为什么它在CustomerController类的joinTable属性中指定为“customer_products”)的原因。 – Pablushka 2012-02-25 20:25:39
我刚刚意识到你正在寻找索引方法中的相关记录。这是阻碍你的递归。看到我上面的更新。 – 2012-02-25 20:52:21
就是这样。非常感谢@Chuck。我会改变主题来反映真正的问题。 – Pablushka 2012-02-26 21:52:42