结果值 - MySQL的

Question

我有这样的表，表1：

+----+-------+----------+ 
| ID | MONTH | QUANTITY | 
+----+-------------+----+ 
| 1 | 1 |  1 | 
| 2 | 2 |  2 | 
| 3 | 7 |  3 | 
| 4 | 4 |  1 | 
| 5 | 2 |  3 | 
| 6 | 12 |  8 | 
| 7 | 1 |  6 | 
+----+-------+----------+ 

My file php is: 

<?php 
include 'bd_cnx.php'; 
$ret =[]; 
    $sql = "SELECT 
      FROM 
      "; 

    $result = $conn->query($sql); 
    if ($result->num_rows > 0){ 

    while($row = $result->fetch_assoc()){ 
     //floatval() transforma sirul numeric in numar 
     $ret[] =[$row['MONTH'], floatval($row['QUANTITY'])]; 
      } 
    } 
    else { 
     echo "result 0"; 
     } 
?> 

我怎样才能返回值，以这种形式？ [[1,7]，[2,5]，[3,0]，[4,1]，[5,0]，[6,0]，[7,3]，[8,0]，[ 9,0]，[10,0]，[11,0]，[12,8]]

谢谢！

Answer 1

下面的代码使用。

$finalArray = $store = []; 
$sql = "SELECT MONTH,SUM(QUANTITY) FROM `stack` GROUP BY MONTH"; 

$result = $conn->query($sql); 
if ($result->num_rows > 0) { 

    while ($row = $result->fetch_assoc()) { 
     //floatval() transforma sirul numeric in numar 
     $store[$row['MONTH']] = $row['QUANTITY']; 
    } 
    $finalArray = '['; 
    for ($i = 1; $i <= 12; $i++) { 
     $finalArray .= "[$i," . (isset($store[$i]) ? $store[$i] : 0) . "]"; 
     if ($i != 12) { 
      $finalArray .= ","; 
     } 
    } 

    $finalArray .= ']'; 
} else { 
    echo "result 0"; 
} 

Answer 2

你可以让你的数据库结果的一个临时数组，然后做一个循环在（固定）组个月（1-12）

$tmp = array(); 
while($row = $result->fetch_assoc()){ 
    $tmp[$row['MONTH']] = $row['QUANTITY']; 
} 

$retTmp = array(); 
for($i=1;$i<=12;$i++){ 
    $retTmp[] = "[$i," .(isset($tmp[$i]) ? $tmp[$i] : 0) . "]"; 
} 
$ret = '[' . implode(',', $retTmp) . ']';